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kodGreya [7K]
3 years ago
7

What is the greatest common factor of 40 and 36

Mathematics
2 answers:
Kazeer [188]3 years ago
7 0

Nobody goes around with lists of greatest common factors in their head. 
When we need to know one, we grab the nearest pencil and work it out.

The factors of  40  are  1,  2,  4,  5,  8,  10,  20, and  40 .

The factors of  36  are  1,  2,  3,  4,  6,  9,  12,  18, and  36 .

The common factors of  35  and  40  are  1,  2, and  4 .

The biggest one is  4 .

lesya692 [45]3 years ago
6 0

The greatest common of 40 and 36 is 4.

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Find surface area of rectangular prism
DIA [1.3K]

Answer:

806 yd sq.

Step-by-step explanation:

Area=(length)(width), so to find the surface area you can just find the area of each side and then add then all together.

They already gave you the length of some of the sides, so you should use that to help you find the length of all the sides.

You can see the entire prism's length is 17 yd, width is 4 yd, and height is 14 yd.

The large visible side's area would be (14)(17)= 283 yd. There's another one of these side's on the other side that we can't see. So we would do (283)(2) = 566 yd sq.

Next, we'll find the area of the side on the side by doing (14)(4)=56. Once again, there's two of these sides so we do (56)(2) to get 112 yd sq for this side.

Finally, we'll find the area of the top side. We can do (4)(17) =68, and then (68)(2) to get 138 yd sq.

Now, we have the area of each side of the prism! To find the total surface area, just add them all together. 556+112+138=806.

The surface area would be 806 yd sq.

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2 years ago
If f(x) = x + 4 and g(x)=x^2-1, what is m(g o f)(x)?
Andreas93 [3]

Until now, given a function  f(x), you would plug a number or another variable in for x. You could even get fancy and plug in an entire expression for x. For example, given  f(x) = 2x + 3, you could find f(y2 – 1) by plugging y2 – 1 in for x to get f(y2 – 1) = 2(y2 – 1) + 3 = 2y2 – 2 + 3 = 2y2 + 1.

In function composition, you're plugging entire functions in for the x. In other words, you're always getting "fancy". But let's start simple. Instead of dealing with functions as formulas, let's deal with functions as sets of (x, y) points:

Let f = {(–2, 3), (–1, 1), (0, 0), (1, –1), (2, –3)} and  

let g = {(–3, 1), (–1, –2), (0, 2), (2, 2), (3, 1)}.  

 

Find (i) f (1), (ii) g(–1), and (iii) (g o f )(1).

(i) This type of  exercise is meant to emphasize that the (x, y) points are really (x, f (x)) points. To find  f (1), I need to find the (x, y) point in the set of (x, f (x)) points that has a first coordinate of x = 1. Then f (1) is the y-value of that point. In this case, the point with x = 1 is (1, –1), so:

8 0
3 years ago
Read 2 more answers
How do you find surface area ? i don't remember. also new friends :) ?
Montano1993 [528]

Answer:

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3 years ago
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Nataly_w [17]

Answer:

13=u

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3 years ago
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mote1985 [20]

Answer:

33

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<em>Add both equations and set equal to 180</em>

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<em>Algebra yeet</em>

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10m +150 = 180

10m = 30

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Angle DBC is (7m + 12):

<em>Substitute m = 3</em>

7(3) + 12 = 21 + 12 = 33 degrees

7 0
3 years ago
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