Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
P=7+7+12+12P=14+24P=38
See the attachment for diagram
<u>Answer</u>:
c = 9
<u>Explanation</u>:
given: f(x)=3x-7
<em>if f(c) =20</em>
To solve this replace x with c and then y is 20.
<u>Solve</u>:
3c - 7 = 20
3c = 27
c = 27 ÷ 3
c = 9
Step-by-step explanation:
When x = -2, x + 2 = (-2) + 2 = 0.
Answer: A = π r2
r=8 and 8 squared is 64 and 64×3.14=200.96 or rounded to the nearest whole number it would be 201
Step-by-step explanation: brainliest please?
