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Nana76 [90]
3 years ago
13

Solve y= -2x + 9 y= 4x -3

Mathematics
2 answers:
wlad13 [49]3 years ago
5 0

y = -2x + 9

y = 4x - 3

y is isolated in both equations, thus you may set the expressions (-2x + 9) and (4x - 3) equal to each other and solve for x.

-2x + 9 = 4x - 3

Subtract 9 from both sides.

-2x + 9 - 9 = 4x - 3 - 9

-2x = 4x - 12

Subtract 4x from both sides.

-2x - 4x = 4x - 12 - 4x

-6x = -12

Divide both sides by -6.

-6x/-6 = -12/-6

x = 2

Substitute 2 for x into one of the original equations to find y.

y = 4x - 3 (given)

y = 4(2) - 3 (substitute)

y = 8 - 3 (multiply)

y = 5 (subtract)

Plug x- and y-values into original equations to check work.

5 = -2(2) + 9

5 = - 4 + 9

5 = 5


5 = 4(2) - 3

5 = 8 - 3

5 = 5

Answer:

x = 2 and y = 5; (2, 5).

Nataly_w [17]3 years ago
4 0

Set the two equations equal to each other, because both equal y

-2x + 9 = 4x - 3

Isolate the x.

-2x (-4x) + 9 (-9) = 4x (-4x) - 3 (-9)

-2x - 4x = - 3 - 9

-6x = -12

Isolate the x. Divide -6 from both sides

-6x/-6 = -12/-6

x = 2

Place 2 for x in one of the equations

y = 4(2) - 3

Solve

y = 8 - 3

y = 5

x = 2, y = 5 is your answer

hope this helps

~Audiomachine

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Xy - 11 = 5 show the direct variation expalin your reasoning
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Read 2 more answers
Newborn babies: A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights
Fed [463]

Answer:

a) 615

b) 715

c) 344

Step-by-step explanation:

According to the Question,

  • Given that,  A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams

  • Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.

Z = (x - mean)/standard deviation

Now,

For x = 4171,  Z = (4171 - 3311)/860 = 1  

  • P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.

Next, multiply that by the sample size of 732.

  • Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171  

 

  • For part b, use the same method except x is now 1591.    

Z = (1581 - 3311)/860 = -2    

  • P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.

 

  • For part c, we now need to get two Z scores, one for 3311 and another for 5031.

Z1 = (3311 - 3311)/860 = 0

Z2 = (5031 - 3311)/860= 2  

P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772

  approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.

5 0
3 years ago
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