Answer:
x=-2 y=-6
Step-by-step explanation:
x-4=4x+2
subtract x from both sides
-4=3x+2
subtract 2 from both sides
-6=3x
divide by 3 on both sides
x=-2
y=-2-4=-6
y=4(-2)+2=-8+2=-6
The standard form of a quadratic equation is

, while the vertex form is:

, where (h, k) is the vertex of the parabola.
What we want is to write

as

First, we note that all the three terms have a factor of 3, so we factorize it and write:

.
Second, we notice that

are the terms produced by

, without the 9. So we can write:

, and substituting in

we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
Since there are three variables and three constants you add like terms.
3(x+15) = 3x + 40
Answer:
1 r= 68/55
2 no solution
Step-by-step explanation: