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prisoha [69]
3 years ago
13

Find the derivative from the first principle y=×3

Mathematics
1 answer:
icang [17]3 years ago
5 0
The derivative of x^3 is 3x^2.... is that what you were looking for?
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Just search it up. Have a nice day :)
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3 years ago
At a picnic, hamburgers and hotdogs were consumed in the ratio 7 to 4. If 41 hamburgers were consumed, how many hot dogs were co
GrogVix [38]
The answer should be 19
8 0
3 years ago
Which expression matches the situation?
ElenaW [278]

Answer:

The expression that matches the situation is 90.00 - 3x ⇒ 1st answer

Step-by-step explanation:

Let us solve the question

∵ You went to the mall with $90.00

→ That means the total money with you  = $90.00

∴ The total money = 90.00 dollars

∵ You bought three shirts that cost x dollars each

∴ The cost of a shirt = $x

∴ The number of shirts = 3

→ Find the total cost of the three shirts

∴ The cost of the shirts = 3 × x

∴ The cost of the shirts = 3x dollars

∵ The money left = the total money - the cost of the shirts

→ Substitute the value of total money and the cost of the shirts

∴ The amount of money left = 90.00 - 3x

∴ You have left with 90.00 - 3x dollars

∴ The expression matches the situation is 90.00 - 3x dollars

3 0
3 years ago
I need help I need help
kobusy [5.1K]

Answer:

click on image

Step-by-step explanation:

click on the image

6 0
2 years ago
Write an equation of the line through (-1,-5) having slope 2/3. give the answer in standard form.
jekas [21]

keeping in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{-5})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-5)}=\stackrel{m}{\cfrac{2}{3}}[x-\stackrel{x_1}{(-1)}]\implies y+5=\cfrac{2}{3}(x+1)

\bf \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y+5)=3\left( \cfrac{2}{3}(x+1) \right)}\implies 3y+15 = 2(x+1) \implies 3y+15=2x+2 \\\\\\ 3y=2x-13\implies -2x+3y=-13\implies 2x-3y=13

7 0
3 years ago
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