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3 years ago

Any suggestions or answers

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

3 0

This is a way to work it out

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Will give brainliest- pls help me overcome my s.tupidness :')

Hunter-Best [27]

Answer:

$3^{3}$

Step-by-step explanation:

$\frac{(3^{4})(3^{2}) }{3^{3} }$

the product rule states that you add exponents when you multiply

$\frac{3^{6} }{3^{3} }$

the quotient rule states that you subtract exponents when you divide

$3^{3}$

8 0

3 years ago

Read 2 more answers

3x+2(x-5)=25 show your work

Zanzabum

Answer:

x = 7

Step-by-step explanation:

Expand 3x+2(x-5)=25 which looks like

3x+2x-10=25

Add similar elements: ( 3x+2x = 5x)

5x-10=25

Add 10 to both sides

5x-10+10 = 25 + 10

Simplfy

5x = 35

Divide both sides by 5

5x ÷ 5 = 35 ÷ 5

Simplfy:

x = 7

have a wonderful day

8 0

3 years ago

Determine whether the two expressions are equivalent. Explain your reasoning.

dlinn [17]

Let us evaluate each pair of expressions one at a time.
8. (n²+4) - n² and 4n.
(n²+4) - n² = n²+ 4 - n² = 4 which is not equal to 4n.
NOT EQUIVALENT

9. 3x + 5 and 2(x + 3)
2(x + 3) = 2x + 6 which is not equal to 3x + 5.
NOT EQUIVALENT

10. 15 - 6x and 15(1 - 6x)
15(1 - 6x) = 15 - 90x which is not equal to 15 - 6x
NOT EQUVALENT

11. (y + y + 2 + y) + 3y and 6y + 2
(y +y +2 + y) + 3y = y+y+y +2 + 3y = 3y + 2 + 3y = 6y + 2.
It matches the other expression.
EQUIVALENT

12. 8y - 3 + 10y and 3(6 - 1)
8y - 3 + 10y = 8y + 10y - 3 = 18y - 3
3(6 - 1) = 3(5) = 15
The two expressions do not match.
NOT EQUIVALENT.

Answer: Only the expressions in number 11 are equivalent.

6 0

2 years ago

Graph the linear equation and answer each of the following questions. y=-2x-3 (A)What is the y-intercept?

balandron [24]

A) The Y-intercept of this equation is 3

B) The slope of this equation is 2

C) This equation has a positive slope

D) Starting from the Y-intercept, I simply went over to the right 1 box, and up 2 boxes

I hope this helps!

5 0

2 years ago

What is 1 and 1/6 minus 7/12 ?

Damm [24]

$1 \frac{1}{6} - \frac{7}{12} \\ 
 \\ 1 \frac{1}{6}= \frac{1x6+1}{6}= \frac{7}{6} \\ 
 \\ \frac{7x2}{6x2}= \frac{14}{12} \\ 
 \\ \frac{7x1}{12x1}= \frac{7}{12} \\ 
 \\ \frac{14}{12} - \frac{7}{12}= \frac{7}{12} \\ 
 \\ Solution: \frac{7}{12} 
$

7 0

3 years ago