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White raven [17]
3 years ago
12

Any suggestions or answers

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
3 0

This is a way to work it out

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Each music class sings 8 songs a week.How many does each class sing in 5 weeks? 6 weeks? 7 weeks?
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Identify the best method for solving the given
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Which option best reflects the message of the cartoon?
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Read 2 more answers
A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time
user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

a(t) = 24t + 2

Velocity:

v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

v(t) = 12t^{2} + 2t + 13

Position:

s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K

Since s(0) = 3

s(t) = 4t^{3} + t^{2} + 13t + 3

What is its position at time t=5?

This is s(5).

s(t) = 4t^{3} + t^{2} + 13t + 3

s(5) = 4*5^{3} + 5^{2} + 13*5 + 3

s(5) = 593

It's position at time t = 5 is 593.

3 0
3 years ago
What is the domain of the function?
ratelena [41]

Answer:

Domain: B but should be x > 0

Range: A

Step-by-step explanation:

The domain is the set of all x values. This is seen in the graph as all values on the x-axis which have a value for the function. Since this function begins at the y-axis (where x = 0) and continues right then the domain is x > 0.

The range is the set of all y values. This is seen in the graph as all values on the y-axis which have a value for the function. Since the function curves on the coordinate plane all along the y-axis, it has no restrictions. This means it has all y values as a part of the function. The range is all real numbers.

4 0
3 years ago
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