Question

7. A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the

Answer 1

Answer: 475.59 meters .

Step-by-step explanation:

The correct equation is the following:

$y =-0 .02x^2 +9.5x + 5.6$

For this exercise you need to use the Quadratic formula:

$x = \frac{-b\±\sqrt{b^2-4ac}}{2a}$

In this case you can identify that the values of "a", "b" and "c" are:

$a=-0.02\\\\b=9.5\\\\c=5.6$

Now you must substitute these values into the Quadratic formula and then evaluate. You get:

$x=\frac{-9.5\±\sqrt{(9.5)^2-4(-0.02)(5.6)}}{2(-0.02)}\\\\x_1=475.588\\x_2=-0.588$

Choose the positive one and round it to the nearest hundreth:

$x_1\approx 475.59$