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Blababa [14]
4 years ago
5

Solve: Find three consecutive even integers such that the sum of the smallest number and twice the middle number is 20 more than

the largest number?
Mathematics
2 answers:
garik1379 [7]4 years ago
4 0

Answer: 8


Step-by-step explanation: 6,7,8 are the consecutive integers because 6+7(2)=20


mylen [45]4 years ago
3 0

We are given

Let's assume

smallest even integer =x

Since, each even integers are difference of 2

so, middle term =x+2

so, largest term =x+2+2=x+4

the sum of the smallest number and twice the middle number is 20 more than the largest number

so, we get

x+2(x+2)=20+x+4

now, we can solve for x

x+2x+4=20+x+4

x+2x+4=x+24

3x+4=x+24

2x=20

Divide both sides by 2

x=10

so, smallest even integer=10

middle even integer=12

largest even integer=14............Answer

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