Solve: Find three consecutive even integers such that the sum of the smallest number and twice the middle number is 20 more than the largest number?
2 answers:
Answer: 8
Step-by-step explanation: 6,7,8 are the consecutive integers because 6+7(2)=20
We are given
Let's assume
smallest even integer =x
Since, each even integers are difference of 2
so, middle term =x+2
so, largest term =x+2+2=x+4
the sum of the smallest number and twice the middle number is 20 more than the largest number
so, we get
now, we can solve for x
Divide both sides by 2
so, smallest even integer=10
middle even integer=12
largest even integer=14............Answer
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