See the attached figure.
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AB = 10 , FD = 3
∵ D is the midpoint of AB, and F is the mid point of CB
∴ FD // AC , FD = 0.5 AC
∵ Δ ABC is a right triangle at C
∴ FD ⊥ BC
∴ BD = 0.5 AB = 5
∴ in Δ FDB ⇒⇒ BF² = BD² - FD² = 5² - 3² = 16
∴ BF = √16 = 4
∵ F is the mid point of CB
∴ CF = BF = 4 , and CB = 2 BF = 2*4 = 8
∵ D is the midpoint of AB, and E is the mid point of AC
∴ DE // CB , and DE = 0.5 CB = 0.5 * 8 = 4
∴ T<span>he length of line ED is 4
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Answer:
f(- 6) = 70
Step-by-step explanation:
To evaluate f(- 6) , substitute x = - 6 into f(x)
f(- 6) = 2(- 6)² - 2 = 2(36) - 2 = 72 - 2 = 70
Answer:
A. A(n) = 150 • (0.74)^n–1 ; 33.29 cm
Step-by-step explanation:
This is a geometric sequence.
a%5B1%5D=1.5m=150cm, r=0.74
The formula is
a%5Bn%5D=a%5B1%5Dr%5E%28n-1%29
Just substitute a1 = 150cm and r = 0.74
a%5Bn%5D=150%280.74%29%5E%28n-1%29
That's the rule.
For the second part, substitute n = 6
cm.
Sherman’s rate would be 17 1/4 miles per hour
Answer:
<h2>N, M and P</h2>
Step-by-step explanation:
N = 16.9 ft²
M = 16π/3 = 16.76 ft²
P = 5π = 15.71 ft²