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skelet666 [1.2K]
3 years ago
6

Write a ratio in three ways, comparing the first quantity to the second.

Mathematics
1 answer:
kkurt [141]3 years ago
5 0
1. 5:2
2. 5/2
3. 5 to 2
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you have a piece of yarn that is 12 1/2 ft long. You need to cut it into strips that are 1 1/4 ft long. how many strips will you
zysi [14]

Answer:

A.

Step-by-step explanation:

12.5/10=1.25.

12.5/8=1.56

12.5/12=1.04

12.5/6=2.08

it's important to know what 1/2 is, 1/3 is, 1/4 is and 1/5 it's also important to know things like 2/2, 2/3, 3/3, 2/4, 3/4, 4/4, 2/5, 3/5, 4/5, and 5/5. You don't need this until 8th grade though. But get on it if you can. Ask your parents or teacher.

5 0
2 years ago
Use the distributive property to write an equivalent expression.<br> 3(8-9)
yulyashka [42]
The solution to this is 3(8)-3(9).
8 0
3 years ago
A lawn mower is pushed a distance of 100 ft. Along a horizontal path by a constant force of 60 lbs. Yhe handle of the lawn mower
stira [4]
For this case we have the following equation:
 w = F • PQ
 Where,
 w: work done
 F: is the force vector
 PQ: is the vector of the direction of movement.
 Rewriting the equation we have:
 w = || F || • || PQ || costheta
 Substituting values:
 w = (60) * (100) * (cos (45))
 w = (60) * (100) * (root (2) / 2)
 w = 4242.640687 lb.ft
 Answer:
 
The work done pushing the lawn mower is:
 
w = 4242.6 lb.ft
7 0
3 years ago
Two drivers, Alison and Kevin, are participating in a drag race. Beginning from a standing start, they each proceed with a const
Vilka [71]

Answer:

Alison wins against Kevin by 0.93 s

Step-by-step explanation:

Alison covers the last 1/4 of the distance in 3 seconds, at a constant acceleration a_a, we have the following equation of motion

s/4 = a_at_a^2/2

where s (m) is the total distance, ta = 3 s is the time

s = 4a_a3^2/2 = 18a_a

a_a = s/18

Similarly, Kevin overs the last 1/3 of the distance in 4 seconds, at a constant acceleration a_k, we have the following equation of motion:

s/3 = a_kt_k^2/2

tk = 4 s is the time

s = 3a_k4^2/2 = 24a_k

a_k = s/24

Since a_a = s/18 we can conclude that a_a > a_k, so Alison would win.

The time it takes for Alison to cover the entire track

s = a_aT_a^2/2

T_a^2 = 2s/a_a = 2s/(s/18) = 36

T_a = \sqrt{36} = 6 s

The time it takes for Kevin to cover the entire track

s = a_kT_k^2/2

T_k^2 = 2s/a_k = 2s/(s/24) = 48

T_a = \sqrt{48} = 6.93 s

So Alison wins against Kevin by 6.93 - 6 = 0.93 s

4 0
3 years ago
-9x^5 + 36x^4 + 189x^3 in factored form
Alex73 [517]

Answer:

-9x^5(x+3)(x-7)

Step-by-step explanation:

factor out -9x^3 from the expression

8 0
3 years ago
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