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4 years ago

A jewellry shop sells 240 necklaces in a month

Mathematics

2 answers:

Basile [38]4 years ago

7 0

Answer:

3:1 would be the most simplified answer

Step-by-step explanation:

I found out what the question was

Colt1911 [192]4 years ago

5 0

Answer:

Ratio is 1:3

Step-by-step explanation:

Given that a jewellery shop sells 240 necklaces in a month. 180 were sold via the shops website, the rest were sold in a high street shop.

We have to work out the ratio for online sales to shop sales

Total sales .. 240

Shop sale .. 180

Online sa .. 60

Hence ratio for online sales:shop sales

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U=(1,2,3,4,5,6,7,8),a=(1,3,5,7), b=(4,5,6) is it true statement

kvv77 [185]

<u>Answer:</u>

U=(1,2,3,4,5,6,7,8), a=(1,3,5,7), b=(4,5,6) is false statement

<u>Solution:</u>

Given, two sets are a = (1, 3, 5, 7) and b = (4, 5, 6).

And their union set is U = (1, 2, 3, 4, 5, 6, 7, 8)

We have to find that whether above sets are true or not.

We know that, union of two sets will have the all elements in the two sets except the repeated elements.

Now, according to our knowledge.

Union of a and b = (1, 3, 5, 7, 4, 6)

Now compare the given union set with our set.

After comparison we can say that, both are not equal which means that given union set is false set.

Hence, given statement is false.

6 0

3 years ago

The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m

UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.7,3.7)$

Where $\mu=14.7$ and $\sigma=3.7$

Since the distribution of X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we have;

$\mu_{\bar X}= 14.70$

$\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59$

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of $\bar X$ Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.7,3.7)$

Where $\mu=14.7$ and $\sigma=3.7$

Since the distribution of X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we have;

$\mu_{\bar X}= 14.70$

$\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59$

4 0

3 years ago

What is the remainder R when the polynomial p(x) is divided by (x - 2)? Is (x - 2) a factor of p(x)?

puteri [66]

Answer:

The answer can be calculated by doing the following steps;

Step-by-step explanation:

5 0

3 years ago

Hello! Need help again

Shtirlitz [24]

Y=-x
Your welcome:):):)

4 0

3 years ago

Mark is purchasing new tiles for his bathrooms. The home improvement store charges $48 for each box of tiles when three or fewer

shutvik [7]

Answer:

f(x)=

1. 48x when x < or = 3,

2. 45x when 4 < or = x < or = 8

3. 42x when 9 < or = x < or = 19

4. 38x when x > 19

Step-by-step explanation:

3 boxes or less = Cost of tiles = $48

4 - 8 boxes ; cost = $45

9 - 19 boxes ; cost = $42

> 19 boxes ; cost = $38

6 0

2 years ago