Answer:
6) - (7m - 4) A. [10m + (-7m)] + [(-6) + 4] B. (10m + 7m) + [(-6) + (-4)] C. [(-10m) + (-7m)] + (6 + 4) D. [10m + (-7m)] + [6 + (-4)]
Step-by-step explanation:
A= 4/32 and 5/40
B= 9/21 and 6/14
C= 2/5 and 16/40
Answer:
As per the statement:
Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.
Let H represents Hawick , A represents Abbotsford and K represents Kelso
See the diagram as shown below:
Distance of AH = 15 miles
Distance of AK = 17 miles.
We have to find the distance HK:
Using Pythagoras theorem;

then;

or
miles.
Therefore, the distance from Hawick to Kelso( to the nearest tenth place) is 22.6 miles
It is equivalent to 4-(-7) = 4+7 = 11
Answer:
You cant find that out. X and Y are like two different animals in a zoo, and XY is a whole other animal, you cant combine two animals in the same cage, so X and Y cant turn into XY. You could do:
X = 5
Y = 2
X + Y = ?
In this case the answer would be seven.