Answer:
a). The total money he has could be the first option (6 one dollar bills, 4 dimes, and 5 pennies)
b). 1,005 cents≠645 cents
c). 60,045 cents≠645 cents
d). 60,405 cents≠645 cents
Step-by-step explanation:
a). Step 1: Consider the total money for the first option
Total money=6 one dollar+4 dimes+5 pennies
where;
6 one dollar=6×1=6 dollars
1 dime=0.10 dollars,
4 dimes=(4×0.1)=0.40 dollars
1 penny=0.01 dollars
5 pennies=5×0.01=0.05 dollars
replacing;
Total money=(6+0.40+0.05)=6.45 dollars
1 dollar=100 cents
6.45 dollars=(6.45×100)=645 cents
The total money he has could be the first option (6 one dollar bills, 4 dimes, and 5 pennies)
b). Step 2: Consider the total money for the second option
Total money=6 one dollar+40 dimes+5 pennies
where;
6 one dollar=6×1=6 dollars
1 dime=0.10 dollars,
40 dimes=(40×0.1)=4 dollars
1 penny=0.01 dollars
5 pennies=5×0.01=0.05 dollars
replacing;
Total money=(6+4+0.05)=10.05 dollars
1 dollar=100 cents
10.05 dollars=(10.05×100)=1,005 cents
1,005 cents≠645 cents
c). Step 3: Consider the total money for the third option
Total money=600 one dollar+4 dimes+5 pennies
where;
600 one dollar=600×1=600 dollars
1 dime=0.10 dollars,
4 dimes=(4×0.1)=0.4 dollars
1 penny=0.01 dollars
5 pennies=5×0.01=0.05 dollars
replacing;
Total money=(600+0.4+0.05)=600.45 dollars
1 dollar=100 cents
600.45 dollars=(600.45×100)=60,045 cents
60,045 cents≠645 cents
d). Step 4: Consider the total money for the fourth option
Total money=600 one dollar+40 dimes+5 pennies
where;
600 one dollar=600×1=600 dollars
1 dime=0.10 dollars,
40 dimes=(40×0.1)=4 dollars
1 penny=0.01 dollars
5 pennies=5×0.01=0.05 dollars
replacing;
Total money=(600+4+0.05)=604.05 dollars
1 dollar=100 cents
604.05 dollars=(604.05×100)=60,405 cents
60,405 cents≠645 cents
