Please help me with all of these!!

You must fast before having bloodwork done for your insurance company. The last time you had something to eat was at 9:30 pm. At

valentinak56 [21]

10 hours and 45 minutes :)

7 0

3 years ago

Read 2 more answers

Just keep getting more homework.<br> i really need help

rusak2 [61]

Answer:

1. x = 1, y = -3

2. x = 3, y = 4

Step-by-step explanation:

Here, we want to solve the sets of simultaneous equations;

a) -y = 5x-2

-3y = -5x + 14

substitute 1 into ii

3(5x-2) = -5x + 14

15x - 6 = -5x + 14

15x + 5x = 14 + 6

20x = 20

x = 20/20

x = 1

from;

-y = 5x - 2

y = -5x + 2

y = -5(1) + 2

y = -3

b) -2y = -6x + 10

2y = x + 5

Substitute ii into i

-(x + 5) = -6x + 10

-x - 5 = -6x + 10

-x + 6x = 10 + 5

5x = 15

x = 15/5

x = 3

2y = x + 5

2y = 3 + 5

2y = 8

y = 8/2

y = 4

4 0

3 years ago

A car salesperson works 40 hours per week at a job where he has two options for being paid. Option A is an hourly wage of $16.

mr_godi [17]

10%

since he works 40 hours per week and gets $16 an hour, that would be 16 * 40 which is 640, so that means he needs a commission rate of 10% as 10% of 6400 is 640.

hope this is helpful!

7 0

3 years ago

Please help links=report and if correct I’ll mark you brainiest

seropon [69]

Answer:

A is the correct answer.

Hope this helps $\mathtt{: )}$

3 0

3 years ago

Regular hexagon ABCDEF is inscribed in circle X and has an apothem that is 6√3 inches long. Use the length of the apothem to cal

Phantasy [73]

Answer:

Part A

$The \ circumradius, \ R = \dfrac{a}{cos \left(\dfrac{\pi}{n} \right)}$

Plugging in the given values we get;

$The \ circumradius, \ R = \dfrac{6 \cdot \sqrt{3} }{cos \left(\dfrac{\pi}{6} \right)} = \dfrac{6 \cdot \sqrt{3} }{\left(\dfrac{\sqrt{3} }{2} \right)} = 6 \cdot \sqrt{3} \times \dfrac{2}{\sqrt{3} } = 12$

R = 12 inches

The radius of the circumscribing circle is 12 inches

Part B

The length of each side of the hexagon, 's', is;

$s = a \times 2 \times tan \left(\dfrac{\pi}{n} \right)$

Therefore;

$s = 6 \cdot \sqrt{3} \times 2 \times tan \left(\dfrac{\pi}{6} \right) = 6 \cdot \sqrt{3} \times 2 \times \left(\dfrac{1}{\sqrt{3} } \right) = 12$

s = 12 inches

The perimeter, P = n × s = 6 × 12 = 72 inches

The perimeter of the hexagon is 72 inches

Step-by-step explanation:

The given parameters of the regular hexagon are;

The length of the apothem of the regular hexagon, a = 6·√3 inches

The relationship between the apothem, 'a', and the circumradius, 'R', is given as follows;

$a = R \cdot cos \left(\dfrac{\pi}{n} \right)$

Where;

n = The number of sides of the regular polygon = 6 for a hexagon

'a = 6·√3 inches', and 'R' are the apothem and the circumradius respectively;

Part A

Therefore, we have;

$The \ circumradius, \ R = \dfrac{a}{cos \left(\dfrac{\pi}{n} \right)}$

Plugging in the values gives;

$The \ circumradius, \ R = \dfrac{6 \cdot \sqrt{3} }{cos \left(\dfrac{\pi}{6} \right)} = \dfrac{6 \cdot \sqrt{3} }{\left(\dfrac{\sqrt{3} }{2} \right)} = 6 \cdot \sqrt{3} \times \dfrac{2}{\sqrt{3} } = 12$

The circumradius, R = 12 inches

Part B

The length of each side of the hexagon, 's', is given as follows;

$s = a \times 2 \times tan \left(\dfrac{\pi}{n} \right)$

Therefore, we get;

$s = 6 \cdot \sqrt{3} \times 2 \times tan \left(\dfrac{\pi}{6} \right) = 6 \cdot \sqrt{3} \times 2 \times \left(\dfrac{1}{\sqrt{3} } \right) = 12$

The length of each side of the hexagon, s = 12 inches

The perimeter of the hexagon, P = n × s = 6 × 12 = 72 inches

The perimeter of the hexagon = 72 inches

5 0

3 years ago