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liberstina [14]
3 years ago
10

Please help links=report and if correct I’ll mark you brainiest

Mathematics
1 answer:
seropon [69]3 years ago
3 0

Answer:

A is the correct answer.

Hope this helps \mathtt{: )}

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Find the ordered pair for the equation: y = 2x + 10 where x = 3
pogonyaev
IT IS 15 BECAUSE YOU HAVE TO ADD IT UP

8 0
3 years ago
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The function f(x) = (x − 4)(x − 2) is shown. What is the range of the function?
leonid [27]

The range of the quadratic function is [-1, ∞) after plotting the function on the coordinate plane.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

It is given that:

The function is:

f(x) = (x - 4)(x - 2)

The above function is a quadratic function.

The above function can be written as:

f(x) = x² - 6x + 8

From the graph,

The minimum value of graph at x = 3 is y = -1

The range of the function is [-1, ∞)

Thus, the range of the quadratic function is [-1, ∞) after plotting the function on the coordinate plane.

Learn more about the function here:

brainly.com/question/5245372

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8 0
1 year ago
Thuy wrote the system of equations. 24 x + 36 y = 72. Negative 16 x + 8 y = 80. If the second equation is multiplied by 3, what
Irina-Kira [14]

Answer:

multiply the first equation by 2

Step-by-step explanation:

24x + 36y = 72

-16x + 8y = 80

48x + 72y = 144

-48x + 24y = 240

96y = 384

y = 4

24x + 36(4) = 72

24x + 144 = 72

24x = -72

x = -3

(-3, 4)

7 0
3 years ago
Read 2 more answers
a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th
hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in ^{5000}C_{10} ways.

Possibility 1: <u>3 tires are blemished.</u>

Total 10 tires can be chosen with 3 blemished tires in ^{1000}C_3 \times {4000}C_7 ways.

Possibility 2:  <u>2 tires are blemished.</u>

Total 10 tires can be chosen with 2 blemished tires in ^{1000}C_2 \times ^{4000}C_8  ways.

Possibility 3: <u>1 tires are blemished.</u>

Total 10 tires can be chosen with 1 blemished tires in ^{1000}C_1 \times^{4000}C_9 ways.

Possibility 4:  <u>No tires are blemished.</u>

Total 10 tires can be chosen with no blemished tires in ^{1000}C_0 \times^{4000}C_{10} ways.

Hence, the required probability is \frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }.

6 0
3 years ago
Graph the solution of y ≥ 1/3x + 4. (points plz)​
Snowcat [4.5K]

Answer:

(0,4) (3,5) (6,6)

Step-by-step explanation:

solid line

shaded above

5 0
3 years ago
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