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3 years ago

How long of the sides?

Mathematics

1 answer:

qaws [65]3 years ago

7 0

Answer:

√85

Step-by-step explanation:

s=[√d1)²+(d2)²]/2

s=(√12²+14²)/2

a=(√340)/2

s=(2√85)/2

s=√85

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Help me please<br> 8. Match each angle pair with the corresponding drawing. Choose the best answer!

sdas [7]

Answer:

1. D

2. B

3. A

4. C

Step-by-step explanation:

1. Vertical angles are a pair of opposite angles formed by the intersection of lines. Choice D has two lines intersecting, and two opposite angles formed by it.

2. Adjacent angles are two angles that have a common vertex and common side but do not overlap. Choice B is two angles with a common vertex and common side, and they don't overlap.

3. Supplementary angles are angles that add up to 180 degrees/make a straight angle. Choice A has two angles that add up to 180 degrees, and the two angles combined make a straight angle/line.

4. Two angles are called complementary angles if they add up to 90 degrees and form a right angle. Choice C has two angles that form a right triangle, meaning it adds up to 90 degrees.

5 0

2 years ago

yLab and Mastering3.3.43Question HelpIn triangle ABC, the measure of angle Bis 15 more than three times the measure of angle A.

lora16 [44]

∠A = 24°

∠B = 87°

∠A = 24°

Explanation:

The sum of angles in a triangle is 180 degrees

let measure of angle A = ∠A

∠B = 15 more than three times the measure of angle A

∠B = 15 + 3∠A

∠C = 45° more than the measure of angle A

∠C = 45° + ∠A

∠A + ∠B + ∠C = 180° (sum of angles in a triangle)

∠A + 15 + 3∠A + 45° + ∠A = 180

collect like terms:

∠A + 3∠A + ∠A + 15 + 45 = 180

5∠A + 60 = 180

5∠A = 180 -60

5∠A = 120

∠A = 120/5

∠A = 24°

∠B = 15 + 3∠A = 15 + 3(24)

∠B = 87°

∠C = 45° + ∠A = 45° + 24°

∠C = 69°

8 0

2 years ago

Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a

hram777 [196]

Answer:

$(1,1)$

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points $(x_1,y_1)\,,\,(x_2,y_2)$ is equal to $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So,

$EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}$

Perimeter of a figure is the length of its outline.

$EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$