All categories

3 years ago

Please help me answer this

Mathematics

2 answers:

Eduardwww [97]3 years ago

7 0

Answer:

The 2nd y is 12, the 3rd y is 24 and the last x is 3

Step-by-step explanation:

Mashutka [201]3 years ago

6 0

Answer:

Put 12 below the 6 and below that put 24 and below 1.5 put 3

Step-by-step explanation:

you have to divide 6/0.75 you get 8 if you do that so then you do 1.5x8=12 so then do 3x8=24 so yeah

You might be interested in

If a horse eats 58 pounds a week, how many pounds does it eat a day? Need two people to answer this 10 points! And Brainliest fo

marta [7]

58 divide 10= 5 remainder 8
(Remember to show your work!)

6 0

3 years ago

The product of 6 and the sum of 3 times a number n and 5

olga nikolaevna [1]

Answer:

Step-by-step explanation:

6 (3n+5)

use the distributive property

18n+35

5 0

4 years ago

What is the value of this product

iren [92.7K]

Answer:

The value of the product is 2²

4 0

1 year ago

6) Find the LMN. And 7) complete the proportionality statement

DanielleElmas [232]

Number 6=b
Number 7=c

3 0

3 years ago

Indicate the sum of the terms in each of the following examples, and simplify the result by combining like terms:

katrin [286]

Answer:

The sum of the terms is equal to $5r^2-14r+3s$ .

The value of the sum at $r=1,s=3$ is 0.

Step-by-step explanation:

Given:

The terms that are given are:

$10r^2, -6r, +5s, -8r, +2s, -5r^2, -4s$

The sum of the terms is the addition of the given terms and is given as:

$=10r^2+ (-6r)+5s+ (-8r)+2s + (-5r^2) + (-4s)$

$=10r^2-6r+5s-8r+2s-5r^2-4s$

Now, combining like terms. Like terms means that are of the same type are grouped together. There are 3 different terms here 'r²', 'r' and 's'.

The terms containing 'r²' are: $10r^2, -5r^2$

The terms containing 'r' are: $-8r, -6r$

The terms containing 's' are: $5s, 2s, -4s$

Now, combining the like terms, we get:

$=(10r^2-5r^2)+(-8r-6r)+(5s + 2s -4s)$

$=(10-5)r^2+(-8-6)r+(5+2-4)s$

$=5r^2+(-14)r+3s$

$=5r^2-14r+3s$

Therefore, the final expression is equal to:

$=5r^2-14r+3s$

Now, plug in $r=1,s=3$ . This gives,

$=5(1)^2-14(1)+3(3)$

$=5\times 1-14+9$

$=5-14+9$

$=0$

Therefore, the value of the sum of all the terms at $r=1,s=3$ is 0.

4 0

3 years ago