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2 years ago

Ummmmm please help me

Mathematics

1 answer:

ivanzaharov [21]2 years ago

4 0

Just look up how to solve volume

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(x+4)(x+11)=0 <br> what do i do

Talja [164]

FOIL first outer inner last it’s distribution

8 0

2 years ago

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Parker has $2,500 in her bank account that earns 3.8% interest annually. How much money will she have in her bank account after

svlad2 [7]

Answer:

$2,860

Step-by-step explanation:

2,500 * 3.8% = 90 in interest a year

90 * 4 = 360 in interest

add that to what she put in

2,860

3 0

3 years ago

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-8 = x divided by 4 + 3

Diano4ka-milaya [45]

Answer:

x = -44

Step-by-step explanation:

-8 = x/4 + 3

-8 - 3 = x/4 + 3 - 3

-11 = x/4

-11 x 4 = (x/4) x 4

-44 = x

7 0

2 years ago

Hi! I need help with the attached question in calc. Thank you:)

Elena L [17]

Answer:

3π square units.

Step-by-step explanation:

We can use the disk method.

Since we are revolving around AB, we have a vertical axis of revolution.

So, our representative rectangle will be horizontal.

R₁ is bounded by y = 9x.

So, x = y/9.

Our radius since our axis is AB will be 1 - x or 1 - y/9.

And we are integrating from y = 0 to y = 9.

By the disk method (for a vertical axis of revolution):

$\displaystyle V=\pi \int_a^b [R(y)]^2\, dy$

So:

$\displaystyle V=\pi\int_0^9\Big(1-\frac{y}{9}\Big)^2\, dy$

Simplify:

$\displaystyle V=\pi\int_0^9(1-\frac{2y}{9}+\frac{y^2}{81})\, dy$

Integrate:

$\displaystyle V=\pi\Big[y-\frac{1}{9}y^2+\frac{1}{243}y^3\Big|_0^9\Big]$

Evaluate (I ignored the 0):

$\displaystyle V=\pi[9-\frac{1}{9}(9)^2+\frac{1}{243}(9^3)]=3\pi$

The volume of the solid is 3π square units.

Note:

You can do this without calculus. Notice that R₁ revolved around AB is simply a right cone with radius 1 and height 9. Then by the volume for a cone formula:

$\displaystyle V=\frac{1}{3}\pi(1)^2(9)=3\pi$

We acquire the exact same answer.

8 0

2 years ago

Which of these expressions CANNOT be simplified by combining like terms?

densk [106]

$5ab^{3} +7-3a^{2} b ^{2} +a^{3}b+10$ can be simplified to by adding the 7 and 10 to get $a^{3}b-3a^{2} b ^{2}+ 5ab^{3} + 17$ .

$5ab^{3}+3a^{2}b^{2}+a^{3}b -10$ cannot be simplified any more by combining like terms.

By distributing the 2b into the parentheses, you can simplify the expression:
$5ab^{3}+2b(3ab^{2})+a^{3}b-10\\
5ab^{3}+6ab^{3}+a^{3}b-10\\
11ab^{3}+a^{3}b-10$

Here you can just add:
$5a^{3}b^{3}+3a^{2}b^{2}+a^{3}b^{3}-10ab\\
6a^{3}b^{3}+3a^{2}b^{2}-10ab$

Thus, the only expression that cannot simplify any more using adding like terms is the second, $5ab^{3}+3a^{2}b^{2}+a^{3}b -10$ .

3 0

3 years ago

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