A)y=-2x+3, y=2B)y=-2x-3, x=2C)y=2x-3, y=2 D)y=2x+3,x=2
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$ 2000 is invested at 3 % interest and $ 4000 is invested at 8 % interest
<em><u>Solution:</u></em>
Given that, total of $6000 was invested
Let "x" be the amount invested at 3 % interest
Then, (6000 - x) is the amount invested at 8 % interest
Given that,
<em><u>The total yearly interest amounted to $380</u></em>
Then, we can frame a equation as:
<em><u>Solve the above expression for "x"</u></em>
Thus, $ 2000 is invested at 3 % interest
(6000 - x) = 6000 - 2000 = 4000
$ 4000 is invested at 8 % interest