Answer:
Let us consider the genes for black individual to be BB.
Let us consider the genes for bluish gray individuals to be BW.
The cross will be:
B W
B BB BW
B BB BW
The results show that there is a 50% probability that the offsprings produced will have black colour. There is also a 50% chance that the offsprings produced will have bluish graycolour.
<em>The genotypic ratio for black individual : bluish gray individual will be 2:2.</em>
<em>The phenotypic ratio for black individual : bluish gray individual will be 2:2</em>.
Answer:
This occurs at the 3′ end position which sits on an mRNA, while a distinct tRNA anticodon triplet sequence matches a three complementary base pair mRNA codon sequence to guide appropriate amino acid into place at a ribosome activation site to form a polypeptide or protein.
Answer:
Lemon juice, lime, grapes, and mostly fruit products
Explanation:
Fruit products are acids used in bakerys for a nice balanced taste with sweetness and sourness.