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alexandr1967 [171]
2 years ago
10

Suppose that at Elkhorn High School, the number of hours per week that seniors spend on homework is approximately Normally distr

ibuted with a mean of 18.6 and a standard deviation of 6.0. Mrs. Habrock takes a simple random sample of 36 seniors and calculates the sample mean homework hours per week. What is the mean of the sampling distribution of means for the 36 students?
Mathematics
1 answer:
Lisa [10]2 years ago
6 0

Answer: mean of sampling distribution of means = 18.6

Step-by-step explanation:

In sampling theory, the population mean is expected to equal to the mean of sampling distribution of means if the estimator is to be a good representative of the population. so, on this note, the mean of sample distribution of means is equal to the population mean = 18.6

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Answer:

=10

Step-by-step explanation:

because 20÷10=2

70÷10=7

50÷10=5

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Add or Subtract to Simplify:<br> (5x + x2 - 4) - (4x - x2 + 6)
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Answer:

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Step-by-step explanation:

Let's simplify step-by-step.

5x+x2−4−(4x−x2+6)

Distribute the Negative Sign:

=5x+x2−4+−1(4x−x2+6)

=5x+x2+−4+−1(4x)+−1(−x2)+(−1)(6)

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Combine Like Terms:

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Exercise 12.1.1: Coin flips and events. About A coin is flipped four times. For each of the events described below, express the
butalik [34]

Answer:

a Pr = 0.25

b Pr = 0.50

c Pr = 0.1875

Step-by-step explanation:

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n = 4 --- number of times

r = 2 --- faces of a coin

First, is to determine the sample size.

This is calculated as:

Size =r^n

Size =2^4

Size =16

Solving (a): First and last slip is head

This event is represented as:

E=\{HHHH, HHTH, HTHH, HTTH\}

The probability is calculated as:

Pr = \frac{n(E)}{Size}

Pr = \frac{4}{16}

Pr = 0.25

b) At least 2 consecutive flips that is heads.

This event is represented as:

E=\{HHHH,HHHT,HHTH,HHTT,THHH,THHT,HTHH,TTHH\}

The probability is calculated as:

Pr = \frac{n(E)}{Size}

Pr = \frac{8}{16}

Pr = 0.50

 

c) First is tail and at least 2 consecutive flips is head.

This event is represented as:

E=\{THHH,THHT,TTHH\}

The probability is calculated as:

Pr = \frac{n(E)}{Size}

Pr = \frac{3}{16}

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