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lys-0071 [83]
3 years ago
13

Here are the prices, rounded to the nearest dollar, of the most frequently purchased gifts in a gift store.

Mathematics
1 answer:
Mariulka [41]3 years ago
4 0
An outlier is a datapoint outside of the first or third quartile +/- 1.5 the inter quartile range

25 33 39 40 41 41 45 46 48 49 51 52 67 73 79

46 is at the center-> median
everything left of it:
25 33 39 40 41 41 45
40 at center=Q1
right of Q2:
48 49 51 52 67 73 79
52 at center=Q3

IQR=Q3-Q1=52-40=12

Q1-1.5*IQR=40-1.5*12=40-18=22
Q3+1.5*IQR=52+1.5*12=52+18=60

so everything <22 or >60 are outliers

so 67,73 and 79 are outliers
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What are the numbers that are either negative or greater than 5
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postive or greater6 7 8 9 10

negative or less 4 3 2 1 0

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3 years ago
suppose that the number of bacteria in a certain population increases according to a continuous exponential growth model. A samp
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Answer:

3.33% per hour

Step-by-step explanation:

Use the A=Pe^rt equation. A is the end amount, so it's 1892. P is the original amount, 1700. E is a constant, around 2.72. R is the growth constant. T is the time that passed, 3 hours. You can substitute the givens into the equation and get 1892=1700e^(3r). Divide by 1700 to isolate the e. This leaves you with 1892/1700=e^(3r). Do the natural log of each side cancel the e and bring the exponent down. This leaves you with ln(1892/1700)=3r. Divide by 3 to isolate r. ln(1892/1700) is .1. .1/3 is .03333. Multiply by 100 to get a percent. 3.33 percent is your final answer.

8 0
3 years ago
What is the distance from the point (a, −b, −4) to the origin?
laiz [17]

Answer:

  \sqrt{a^2+b^2+16}

Step-by-step explanation:

The distance (d) between two points in 3 dimensions is ...

  d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)

Then the distance between (a, -b, -4) and (0, 0, 0) is ...

  d = √((a -0)² +(-b -0)² +(-4 -0)²)

  = √(a² +b² +16)

6 0
3 years ago
assuming a trucker changes his tires every for 40,000 miles and that he starts with a brand new set of tires how many sets of ti
sdas [7]
80,000 tires will be used
8 0
3 years ago
When the effective interest rate is 9% per annum, what is the present value of a series of 50 annual payments that start at $100
ser-zykov [4K]

Answer:

$1,109.62

Step-by-step explanation:

Let's first compute the <em>future value FV.</em>  

In order to see the rule of formation, let's see the value (in $) for the first few years

<u>End of year 0</u>

1,000

<u>End of year 1(capital + interest + new deposit)</u>

1,000*(1.09)+10  

<u>End of year 2 (capital + interest + new deposit)</u>

(1,000*(1.09)+10)*1.09 +10 =

\bf 1,000*(1.09)^2+10(1+1.09)

<u>End of year 3 (capital + interest + new deposit)</u>

\bf (1,000*(1.09)^2+10(1+1.09))(1.09)+10=\\1,000*(1.09)^3+10(1+1.09+1.09^2)

and we can see that at the end of year 50, the future value is

\bf FV=1,000*(1.09)^{50}+10(1+1.09+(1.09)^2+...+(1.09)^{49}

The sum  

\bf 1+1.09+(1.09)^2+...+(1.09)^{49}

is the <em>sum of a geometric sequence </em>with common ratio 1.09 and is equal to

\bf \frac{(1.09)^{50}-1}{1.09-1}=815.08356

and the future value is then

\bf FV=1,000*(1.09)^{50}+10*815.08356=82,508.35564

The <em>present value PV</em> is

\bf PV=\frac{FV}{(1.09)^{50}}=\frac{82508.35564}{74.35572}=1,109.616829\approx \$1,109.62

rounded to the nearest hundredth.

5 0
3 years ago
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