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lawyer [7]
3 years ago
15

Matt can buy an 8-ounce jar of salsa for $2.79 or a 15-ounce jar of salsa for $5.54. Which jar has the best unit rate?

Mathematics
1 answer:
katrin [286]3 years ago
3 0

Answer:

15 ounce

Step-by-step explanation:

a

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Simplify: 2{10-5+x[1+3(6-2)]}
REY [17]

Answer:

10+26x

Step-by-step explanation:

To solve this, work your way from the inner most parentheses to the outer most:

  1. The inner most parentheses is around 6-2, meaning you solve this first. When you solve this, you get 4.
  2. The second most inner parentheses is around (1+3 times 4) using PEMDAS, you first solve the multiplication, and then add. Once you solve this, you get 13.
  3. Next, the outer most parentheses is around (10-5+13x). When you simplify this, you get 5+13x
  4. Finally, you multiply 2(5+13x). Using distributive property, you get 10+26x as your final simplified answer.
3 0
3 years ago
10 POINTS! Answer ASAP. Answer Choices: Angle 1, Angle 2, Angle 3, Angle 4, Angle 5
MrRa [10]

Answer:

Angle 4

Step-by-step explanation:

theyre alternate interior angles

please mark me brainliest if I’m right!,

6 0
2 years ago
Read 2 more answers
A student comes to lecture at a time that is uniformly distributed between 5:09 and 5:14. Independently of the student, the prof
scZoUnD [109]

Answer:

1/2

Step-by-step explanation:

The lecture has already begun when the student arrives means one of these scenarios happen:  

1) the class started at 5:10 and the student arrives at 5:11 or 5:12 or 5:13 or 5:14

2) the class started at 5:11 and the student arrives at 5:12 or 5:13 or 5:14

3) the class started at 5:12 and the student arrives at 5:13 or 5:14

Given student time of arrival is uniformly distributed, then the probability he/she arrives at 5:09 or 5:10 or 5:11 or 5:12 or 5:13 or 5:14 is 1/6.

So,  the probability that the student arrives between 5:11 and 5:14 is 1/6 + 1/6 + 1/6 + 1/6 = 2/3.

The probability that the student arrives between 5:12 and 5:14 is 1/6 + 1/6 + 1/6 = 1/2.

The probability that the student arrives at 5:13 or 5:14  is 1/6 + 1/6 = 1/3.

Given class starting time is uniformly distributed, then the probability it starts at 5:10 or  5:11 or 5:12 is 1/3.

Given the two events are independent, the probability of the first scenario is: (1/3)*(2/3) = 2/9

For the second scenario:  (1/3)*(1/2) = 1/6

For the third scenario:  (1/3)*(1/3) = 1/9

Because all of these scenarios are mutually exclusive the total probability of one of them happen is: 2/9 + 1/6 + 1/9 = 1/2

3 0
2 years ago
How can I use benchmarks to estimate 9/10+4/10
Jobisdone [24]
I don’t kno how to estimate using benchmarks but I kno the exacts answer is 13/10 or 1.3
4 0
2 years ago
I need help to solve this question.
LekaFEV [45]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
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