Peter's account is 910-40x, and Marla's account is 470-2x. This is a system, so you must find the number that makes both equations end up with the same number. Basically trial and error. Here is what I did:
Let's try the number 10. 910-400=510 and 470-20=450. I need a higher number.
Let's try 13 next. 910-520=390 and 470-26=444. Now the number has to be lower.
Let's try 12. 910-480=430 and 470-24=446. Close, and a little lower.
11.5 is too low, and 11.7 is too high. 11.6 has Equation 1 at 446 and Equation 2 at 446.8. Very close!
It is somewhere around 11.6. I hope that this can give you a start in figuring it out, because I don't believe in giving the complete answer, because then you do not learn anything from it.
6x-21>3
Add 21 to both sides
6x>24
Divide 6 on both sides
X>4
14x+11>-17
Subtract 11 from both sides
14x>-28
Divide 14 on both sides
X<-2
Answer:
Both Lindsay and Sharon are wrong.
Step-by-step explanation:
When Lindsay was doing her problem, she put 100 on the bottom and 45 on the top, when it should have been the other way around.
Sharon would have been correct if she had used the right measuring unit. 2/5 of a milliliter should have been 2/5 of a liter.
Answer:
y= 48 + 0.1x
x= miles driven
Step-by-step explanation:
<u>We need to calculate the fixed and variable cost (per mile) of renting a car. To do that, we will use the high-low method:</u>
Variable cost per unit= (Highest activity cost - Lowest activity cost)/ (Highest activity units - Lowest activity units)
Variable cost per unit= (65 - 58) / (170 - 100)
Variable cost per unit= $0.1 per mile
Fixed costs= Highest activity cost - (Variable cost per unit * HAU)
Fixed costs= 65 - (0.1*170)
Fixed costs= $48
Fixed costs= LAC - (Variable cost per unit* LAU)
Fixed costs= 58 - (0.1*100)
Fixed costs= $48
y= 48 + 0.1x
x= miles driven
Depreciation of 11% per year means that the price is multiplied by 89% (0.89) every year. Do this 11 times or use exponents
Final price:
207000*(0.89^11) = 57446.083
