The answer to this question is: 17
Answer:
0.9177
Step-by-step explanation:
let us first represent the two failure modes with respect to time as follows
R₁(t) for external conditions
R₂(t) for wear out condition ( Wiebull )
Now,

where t = time in years = 1,
n = failure rate constant = 0.07
Also,

where t = time in years = 1
where Q = characteristic life in years = 10
and B = the shape parameter = 1.8
Substituting values into equation 1

Substituting values into equation 2

let the <em>system reliability </em>for a design life of one year be Rs(t)
hence,
Rs(t) = R1(t) * R2(t)
t = 1
![Rs(1) = [e^{-0.07} ] * [e^{-0.0158} ] = 0.917713](https://tex.z-dn.net/?f=Rs%281%29%20%3D%20%5Be%5E%7B-0.07%7D%20%5D%20%2A%20%5Be%5E%7B-0.0158%7D%20%5D%20%3D%200.917713)
Rs(1) = 0.9177 (approx to four decimal places)
The length of the measure of YZ is 80cm
<h3>Perpendicular lines</h3>
Perpendicular lines are lines that are at angle 90 degrees to each other. From the given diagram;
WX = 82cm
Required
Length. of YZ
Using the pythagoras theorem
YV = VZ = √41²-9²
YV = VZ = √1600
YV = VZ = 40
Since YZ = YV + VZ
YZ = 40cm + 40cm
YZ= 80cm
Hence the length of the measure of YZ is 80cm
Learn more on perpendicular lines here: brainly.com/question/1202004
#SPJ1
Answer:
×=12
Step-by-step explanation:
30+6= 36
36÷3=12
hope it helps
- - Let's solve for C.
Starting off with our equation:

Transform:

Solve for that:

Solve for that for the last time and your answer is