Question

What is the point-slope form of a line with slope 3 that contains the point (2,1)

Answer 1

Answer:

y-1=3(x-2)

Step-by-step explanation:

The point-slope form of a line is

$y-y_{1} =m(x-x_{1} )$

where m denotes slope of line and $(x_{1} ,y_{1} )$ is a point on line.

From question statement,we observe that

m= 3 and $(x_{1} ,y_{1} )$=(2,1)

putting above values in point-slope form of line,we get

y-1=3(x-2) is point slope form of a line with slope 3 that contains the point (2,1).

Answer 2

Answer:

Point slope form:

The equation of line is given by: $y-y_1=m(x-x_1)$        .....[1]

where m is the slope and a line contains a point $(x_1, y_1)$.

As per the given statement:

Slope(m) = 3

$(x_1, y_1)$. = (2, 1)

Substitute these in [1] we have;

$y-1=3(x-2)$

therefore, the point slope form of a line with slope 3 that contains the point (2, 1) is; $y-1=3(x-2)$