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Nikolay [14]
3 years ago
7

Use function notation to represent how much the volume of the box (in cubic inches) changes by if the cutout length increases fr

om 0.3 inches to 1.2 inches.
Mathematics
1 answer:
MakcuM [25]3 years ago
7 0

Answer:

Increases 64 times

Step-by-step explanation:

The volume of the box can be calculated using formula

V=l\cdot w\cdot h,

where

V = volume,

l = length,

w = width,

h = height

If the length was 0.3 inches, then the volume was

V_1=0.3\cdot w\cdot h=0.3wh

When the length became 1.2 inches, then all dimensions became 1.2 :0.3 =4 times greater, then the volume was

V_2=1.2\cdot (4w)\cdot (4h)=19.2wh

The volume increases

\dfrac{V_2}{V_1}=\dfrac{1.92wh}{0.3wh}=64 times

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larisa86 [58]

From the solution of the expression, it can be seen that s = 6 when t = 3 while t = 1 when s = 2.

<h3>How do we solve a mathematical expression?</h3>

Given:

(12t) = (6s) ........................ (1)

When t = 3, we can solve for s from the expression in equation (1) by substituting t = 3 into the equation as follows:

12 * 3 = 6s

36 = 6s

s = 36 / 6

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When s = 2, we can solve for t from the expression in equation (1) by substituting s = 2 into the equation as follows:

12t = 6 * 2

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2 years ago
Total profit P is defined as total revenue R -= total cost​ C, and is given by the function Upper P left parenthesis x right par
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Answer:

Step-by-step explanation:

P(x) = R(x) - C(x)

Where,

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R(x) = Total revenue

C(x) = Total cost

R(x)equals150.97 x minus 0.3 x squared

R(x) = 150.97x - 0.3x^2

Upper C left parenthesis x right parenthesis equals 4529.10 plus 0.5 x squared.

C(x) = 4529.10 + 0.5x^2

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= (150.97x - 0.3x^2) - ( 4529.10 + 0.5x^2)

= 150.97x - 0.3x^2 - 4529.10 - 0.5x^2

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3 years ago
Solve for x -3 + x <br> = - 38
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in a marathon race (42.195 km), the winner’s time is 2 hours, 13 minutes, and 9 seconds, while the second-place time is 2 hours,
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in a marathon race (42.195 km), the winner’s time is 2 hours, 13 minutes, and 9 seconds, while the second-place time is 2 hours, 26 minutes, and 6 seconds . The distance is 2.664 km.

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distance of the second place holder from the finish line is given as

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D'= 2.664 km

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