Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
________________________________
now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Answer:
79.6
Step-by-step explanation:
4 3/5+15÷1/5
23/5+15÷1/5
4.6+15÷0.2
4.6+75
79.6
9514 1404 393
Answer:
C. 2×5²
Step-by-step explanation:
The prime factors of 50 are ...
50 = 2×5×5 = 2×5² . . . . . matches choice C
Answer:
1/20
Step-by-step explanation:
Remark: Not huge
Total number of Socks: 6 + 6 + 4 = 16
P(First Black Sock): 4/16 = 1/4
The second Sock needs to be discussed a bit. The number of black socks has gone down to 1 and the total will always go down by 1.
Second Sock: 3 Black / 15 Total = 3/15 = 1/5
Combined Probability: 1/4 * 1/5 = 1/20
It’s 30m,
18msq/m + 4m x 3
= 18 m + 12m
= 30 m
