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NISA [10]
4 years ago
8

Use the diagram to answer the question. Triangle R S T. Segment R S measures 10 units Segment R T measures 8 units. Angle T is a

right angle. What is the measure of ∠R? Enter the correct value rounded to one decimal place, if necessary, like this: 42.5

Mathematics
2 answers:
Sergio [31]4 years ago
8 0

Answer:

Step-by-step explanation:

Daniel [21]4 years ago
7 0

Answer:

angle R= 36.869

Step-by-step explanation:

CosR=8/10

cosR=0.8

R= inverse cos (0.8)

R=36.869

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What is 119,000,093 in two other forms
Sladkaya [172]
1. (1*100,000,000)+(1*10,000,000)+(9*1,000,000)+(9*10)+(3*1)= (expanded form) 2. one hundred nineteen million  ninety three. ( worded form)
3 0
3 years ago
Aisha can walk 9 miles in 2 hours. At this rate, how many miles will she walk during the week if she walks a total of 6 hours?
Nikolay [14]

Answer: Aisha can walk 27 miles during the week if she walks a total of 6 hours.

Step-by-step explanation:

9/2=4.5

4.5*6=27

3 0
4 years ago
Read 2 more answers
A brewery has a beer dispensing machine that dispenses beer into the company's 12 ounce bottles. The distribution for the amount
-Dominant- [34]

Answer:

The company should use a mean of 12.37 ounces.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The distribution for the amount of beer dispensed by the machine follows a normal distribution with a standard deviation of 0.17 ounce.

This means that \sigma = 0.17

The company can control the mean amount of beer dispensed by the machine. What value of the mean should the company use if it wants to guarantee that 98.5% of the bottles contain at least 12 ounces (the amount on the label)?

This is \mu, considering that when X = 12, Z has a p-value of 1 - 0.985 = 0.015, so when X = 12, Z = -2.17.

Then

Z = \frac{X - \mu}{\sigma}

-2.17 = \frac{12 - \mu}{0.17}

12 - \mu = -2.17*0.17

\mu = 12 + 2.17*0.17

\mu = 12.37

The company should use a mean of 12.37 ounces.

7 0
3 years ago
What’s the answer for this problem <br> A. 11<br> B. 5 <br> C. -5
Lina20 [59]

your answer would be B. 5

3 0
4 years ago
Read 2 more answers
Work out the weekly mean number of 50 kg bags of flour used in these 5 weeks
bogdanovich [222]

Answer:

Weekly Mean Number of 50-kg bags =10.8 bags

Step-by-step explanation:

In Week 1, Kim uses 7  50kg bags of flour

In Week 2, Kim uses 14  50kg bags of flour

In Week 3, Kim uses 8 X 50kg bags of flour

In Week 4, Kim uses 13 X 50kg bags of flour

In Week 5, Kim will make 2400 loaves.

Each of these loaves will need 250g of flour.

Total Mass of flour that will be used =2400 X 250=600,000 grams

600,000$ grams=600,000 \div 1000$ kg =600kg\\Number of 50-kg bags =600 \div$ 50 =12 bags

In Week 5, Kim will use 12 bags.

Therefore:

Weekly Mean number of 50kg bags of flour used in these 5 weeks.

=\dfrac{7+14+8+13+12}{5}\\\\ =\dfrac{54}{5}\\\\=10.8 \\ \approx 11$ bags

4 0
3 years ago
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