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jekas [21]
3 years ago
6

A blueprint has a scale of 2 inches = 2 feet. What is the scale factor of the blueprint?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
3 0
1 in = 1 ft 

there are 12 inches in a foot...

you could say that 1 inch = 12 inches, or that the scale is 1:12
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She started with 200 stamps

Step-by-step explanation:

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For 23-25, use the table.
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Jon and Gina are different we’re opposite
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I need help please. The question is already there. Tysm. 20 points.
Bess [88]

Answer:

$109 and 35%

Step-by-step explanation:

49.05 is the sale price and the discount is 55%. What’s the original price?

price/ 1- discount

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5 0
3 years ago
Help me find the range of this function please
lara31 [8.8K]

Answer:

{-2, -14, -26, -50}

Step-by-step explanation:

The range of the function is the function evaluated at each point of the given domain. So to find the range of the function we need to find the value of the function for each point in the domain:

- For x = -8

f(x)=-2x-18

f(-8)=-2(-8)-18

f(-8)=16-18

f(-8)=-2

The first value of the range of the function is -2

- For x = -2

f(x)=-2x-18

f(-2)=-2(-2)-18

f(-2)=4-18

f(-2)=-14

The second value of the range is -14

- For x = 4

f(x)=-2x-18

f(4)=-2(4)-18

f(4)=-8-18

f(4)=-26

Th third values of the range is -26

- For x = 16

f(x)=-2x-18

f(16)=-2(16)-18

f(16)=-32-18

f(16)=-50

The fourth and last value of the range is -50

Now we can put all the values of the range together

The range of the function is {-2, -14, -26, -50}

8 0
3 years ago
Write the equation of the sphere in standard form. x^2 + y^2 + z^2 + 2x − 4y − 6z = 22
madam [21]

The equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Given equation of sphere be x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We are required to express the given equation in the standard form of the equation of sphere.

Equation is basically relationship between two or more variables that are expressed in equal to form. Equation of two variables look like ax+by=c. It may be linear equation,quadratic equation, cubic equation or many more depending on the powers of variables. The standard form of the equation of sphere looks like  x^{2} +y^{2} +z^{2} =r^{2}.

The given equation is x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We have to break 22 which is in right side into various parts according to the left side of the equation.

x^{2} +y^{2} +z^{2} +2x-4y-6z=-1-4-9+36

x^{2} +y^{2} +z^{2} +2x-4y-6z+1+4+9=36

x^{2} +1+2x+y^{2}+4-4y+z^{2} +9-6z=36

x^{2} +(1)^{2} +2*1*x+y^{2} +(2)^{2} -2*2y+z^{2} +(3)^{2} -2*3z=36

(x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}

Hence the equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Learn more about equations at brainly.com/question/2972832

#SPJ4

7 0
1 year ago
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