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Svetllana [295]
3 years ago
8

Factor 56n2-8n-7n+1 by grouping.

Mathematics
2 answers:
trapecia [35]3 years ago
8 0
56n^2 - (8n-7n) + 1
d1i1m1o1n [39]3 years ago
4 0
\bf 56n^2-8n-7n+1\implies (56n^2-8n)-(7n-1)
\\\\\\
8n(7n-1)~~-~~(7n-1)\implies \stackrel{common~factor}{(7n-1)}[8n-1]
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A privately owned lake contains two types of game fish, bass and trout. The owner provides two types of food, A and B, for these
Vinvika [58]

Answer:

133 fishes

Step-by-step explanation:

Units of food A = 400 units

Units of food B = 400 units

Fish Bass required 2 units of A and 4 units of B.

Fish Trout requires 5 units of A and 2 units of B.

i. For food A,

total units of food A required = 2 + 5

                                                 = 7 units

number of bass and trout that would consume food A = 2 x \frac{400}{7}

                                               = 114.3

number of bass and trout that would consume food A = 114

ii. For food B,

total units of food B required = 4 + 2

                                                = 6 units

number of bass and trout that would consume food B = 2 x \frac{400}{6}

                                                 = 133.3

number of bass and trout that would consume food B = 133

Thus, the maximum number of fish that the lake can support is 133.

4 0
3 years ago
Mara carried water bottles to the field to share with her team at halftime. The water bottles weighed a total of 60x^2 + 48x + 2
VLD [36.1K]

Answer:

b)\: 12(5x^2+4x+2)

Step-by-step explanation:

The given expression for water bottles is

60x^2+48x+24.


The highest common factor of all the terms of this expression is 12.


We now factor to obtain;

12(5x^2+4x+2)

Hence the the factorization that represents the number of water bottles and the weight of each bottle is the one in option B.

The correct answer is B


We therefore factor to obtain,


3 0
4 years ago
First pirson to type 1 i will see if i can give brainlist but idk how bot i will try
amm1812

Answer:

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Step-by-step explanation:

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3 years ago
Johnny is reading a novel for the read-a- Thon. The ratio of the number of pages she read to the pages that remain to be read is
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There are several ways to answer this question and I will use this approach. Since Johnny reads at a ratio of 7:3 it can be stated that for every 10 pages in a book containing 500 pages Johnny will read 7 of those pages. There are 50 groups of 10 in a 500-page book (50 x 10). Take the ration 7:3 times 50 and use the distributive property:  7:3(50) = (7 x 50):(3 x 50) = 350:150. Based on this Johnny has read 350 pages and has 150 pages remaining.
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4 years ago
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