All categories

1 year ago

Round the number to the place value given87.945327 rounded to the hundred- thousandth is

Mathematics

1 answer:

dem82 [27]1 year ago

8 0

Let us identify the different place values in the given number.

$87.945327$

Starting from the left side, we have:

8 - ten's place

7 - one's place

decimal point

9 - tenth's place

4 - hundredths place

5 - thousandths place

3 - ten-thousandths place

2 - hundred-thousandths place

7 - millionth place

As we can see above, the number in the hundred-thousandths place is 2.

The number after 2 or the number in the millionth place is 7. Since the number in the millionth place is above 5, we will round up the hundred-thousandths place by adding 1. So, 87.945327 becomes 87.94533 when rounded to the hundred-thousandth place.

You might be interested in

The standard divination of a set of data is 9.5 the mean is 205 what is the margin of error

skelet666 [1.2K]

Step-by-step explanation:

Margin of error = critical value × standard deviation

We aren't given the critical value or any information to calculate it, so we need to make some assumptions. Assuming the data set is large enough to be approximated as normal, and that the confidence level is 95%, then the critical value is 1.96.

ME = 1.96 × 9.5

ME = 18.62

You may choose to round 1.96 to 2, in which case the margin of error is:

ME = 2 × 9.5

ME = 19

8 0

4 years ago

The compound interest on a sum of money in

Yakvenalex [24]

Answer:

The difference between the principal and the compound interest in three years is Rs 17,994

Step-by-step explanation:

The compound interest is given according to the following formula;

$C.I. = P \cdot \left ( 1 + \dfrac{r}{n} \right ) ^{n\cdot t} - P$

The given amount of the compound after 2 years = Rs 5,460

The given amount of the compound after 4 years = Rs 12,066.60

Therefore, we have;

$5,460 = P \cdot \left ( 1 + \dfrac{r}{100} \right ) ^{2} - P$ ...(1)

$12,066.60 = P \cdot \left ( 1 + \dfrac{r}{100} \right ) ^{4} - P$ ...(2)

Dividing equation (2) by (1), we have;

$\dfrac{12,066.60}{5,460} = \dfrac{P \cdot \left ( \left ( 1 + \dfrac{r}{100} \right ) ^{4} - 1\right )}{P \cdot \left (\left ( 1 + \dfrac{r}{100} \right ) ^{2} -1 \right ) } =\dfrac{\left ( 1 + \dfrac{r}{100} \right ) ^{4} - 1}{\left ( 1 + \dfrac{r}{100} \right ) ^{2} -1 }$

$Let \ \left ( 1 + \dfrac{r}{100} \right ) ^{2} = x, we \ get;$

$\dfrac{12,066.60}{5,460} =\dfrac{\left ( 1 + \dfrac{r}{100} \right ) ^{4} - 1}{\left ( 1 + \dfrac{r}{100} \right ) ^{2} -1 } = \dfrac{x^2 - 1}{x - 1}$

∴ 12,066.60 × (x - 1) = 5,460 × (x² - 1) = 5,460 × (x - 1) ×(x + 1)

∴ 12,066.60 × (x - 1)/(x - 1) = 5,460 × (x + 1)

12,066.60/5,460 = x + 1

x = 12,066.60/5,460 - 1 = 1.21 = 121/100

x = 121/100

$\left ( 1 + \dfrac{r}{100} \right ) ^{2} = x = \dfrac{121}{100}$

$1 + \dfrac{r}{100} =\sqrt{ \dfrac{121}{100}} = \dfrac{11}{10}$

We get

$\dfrac{12,066.60}{5,460} =\dfrac{221}{100}$

$\therefore \dfrac{12,066.60}{5,460} =\dfrac{221}{100} = \left ( 1 + \dfrac{r}{100} \right ) ^{2}$

$1 + \dfrac{r}{100} = \sqrt{ \dfrac{221}{100} } = \dfrac{\sqrt{221} }{10}$

$\dfrac{r}{100} = \dfrac{\sqrt{221} }{10} - 1$

$\dfrac{r}{100} = \dfrac{11}{10} - 1 = \dfrac{1}{10} = 0.1$

r = 100 × 0.1 = 10%

r = 10%

Therefore, we have;

$5,460 = P \cdot \left ( 1 + \dfrac{r}{100} \right ) ^{2} - P = P \times \left ( 1 + 0.1\right ) ^{2} - P$

$5,460 = P \times \left ( 1 + 0.1\right ) ^{2} - P = P \times \left (\left ( 1 + 0.1\right ) ^{2} - 1\right) = P \times \dfrac{21}{100}$

$P = \dfrac{100}{21} \times 5,460 = 26,000$

The principal = Rs. 26,000

The compound interest in 3 years is therefore;

$CI_3 = 26,000 \times \left ( 1 + \dfrac{10}{100} \right ) ^{3} - 26,000= 8606$

The difference, 'd', between the principal and the compound interest in three years, is given as follows;

d = P - CI₃

d = 26,600 - 8606 = 17994

The difference between the principal and the compound interest in three years, d = Rs 17,994.

5 0

3 years ago

Question 3 (25 points) Shopping at Saver Mart, Lisa buys her children four shirts and three pairs of pants for $85.50. She retur

cupoosta [38]

The system of equations that represent the cost of x shirts, and y pairs of pants are 4x + 3y = 85.50 and 3x + 5y = 115.00. Option (a) is correct.

A system of equations or an equation system is a collection of simultaneous equations.

Given that Shopping at Saver Mart, Lisa buys her children four shirts and three pairs of pants for $85.50 and She returns the next day and buys three shirts and five pairs of pants for $115.00

Now we have to find the system of equation

Lisa buys her children four shirts and three pairs of pants for $85.50 is given by

4x + 3y = 85.50

She buys three shirts and five pairs of pants for $115.00 is given by

3x + 5y = 115.00

Therefore the system of equations that represent the cost of x shirts, and y pairs of pants are

4x + 3y = 85.50 and 3x + 5y = 115.00

To learn more about system equations visit

brainly.com/question/21620502

#SPJ9

6 0

1 year ago

PLEASE HELP PRECALC WHAT IS THE SECOND ROW MULTIPLIED BY?

Charra [1.4K]

Answer:

the answer is .5 i think

4 0

3 years ago

Read 2 more answers

12x-5y=20 y=x+4<br> 3x+y=3 x=-y+3

Vladimir79 [104]

Standard form (which I assume is what they want you to turn these into) is y=mx+b.

12x-5y=20 is y=2.4x-4.
Subtract 12x from both sides, -5y=-12x+20.
Multiply both sides by -1, 5y=12x-20.
Divide both sides by 5, y=2.4x-4.

y=x+4 is already in standard form- I'm not quite sure what to do.

3x+y=3 is y=-3x+3.
Subtract 3x from both sides, y=-3x+3.

x=-y+3 is y=-x+3
Ad y to both sides, y+x=3.
Subtract x from both sides, y=-x+3.

4 0

3 years ago