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malfutka [58]
1 year ago
11

Round the number to the place value given87.945327 rounded to the hundred- thousandth is

Mathematics
1 answer:
dem82 [27]1 year ago
8 0

Let us identify the different place values in the given number.

87.945327

Starting from the left side, we have:

8 - ten's place

7 - one's place

decimal point

9 - tenth's place

4 - hundredths place

5 - thousandths place

3 - ten-thousandths place

2 - hundred-thousandths place

7 - millionth place

As we can see above, the number in the hundred-thousandths place is 2.

The number after 2 or the number in the millionth place is 7. Since the number in the millionth place is above 5, we will round up the hundred-thousandths place by adding 1. So, 87.945327 becomes 87.94533 when rounded to the hundred-thousandth place.

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Change 15/4 to mixed number
MA_775_DIABLO [31]
15/4

how many times does 4 go into 15 without going over.....that would be 3 times....so 3 is ur whole number. 3 * 4 = 12......15 - 12 = 3...and 3 is ur numerator....the denominator stays the same

so ur answer is : 3 3/4
7 0
3 years ago
Help i,m suck and i cant find the answer
Anestetic [448]
The answer is 2x
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3 years ago
Rewrite the expression as a single exponent
kifflom [539]

Answer:

9^7

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the solution to the equation 3/m+3-m/3-m=m^2+9/m^2-9
Bas_tet [7]

Answer:

  no solution

Step-by-step explanation:

If we subtract the left side of the equation, we get ...

  \dfrac{m^2+9}{m^2-9}-\dfrac{3}{m+3}+\dfrac{3}{3-m}=0\\\\\dfrac{m^2+9-3(m-3)-3(m+3)}{(m-3)(m+3)}=0\\\\\dfrac{m^2-6m+9}{(m-3)(m+3)}=0=\dfrac{(m-3)^2}{(m-3)(m+3)}\\\\\dfrac{m-3}{m+3}=0\quad\text{m$\ne$3}

This equation will equal zero only if m=3, which is disallowed because it makes the denominator zero. Thus, there is no solution.

7 0
3 years ago
Could anyone solve this equation
Ainat [17]
I)
8 - 3x = 23
-3x = 15
x = -5

ii)
5x - 16 = 34
5x = 50
x = 10

iii)
2 - 5x = -3
-5x = -5
x = 1
6 0
3 years ago
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