The two diagonals intersects at right-angle for a kite
the long diagonal also bisects the short diagonal so QP = PS = QS/2 = 6/2 = 3
QPR is a right-angle triangle with QR at 5 and QR at 3
RP = sqrt (5^2 - 3^) = 4m
Vertex form: y = a(x - h)² + k
h = 2
k = -1
y = 0
x = 5
0 = a(5 - 2)² - 1
0 = 9a - 1
a = 1/9
Answer:
1005
Step-by-step explanation:
10 to the third power + 5 =
1000 + 5 =
1005
Hope that helps!
1. ∠1 is complementary to ∠2. 1. givem
2. m∠1 + m∠2. 2. Definition of complementary
3.BD bisects ∠ADC. 3. Given
4. 4. Definition of bisect
5. m∠2 = m∠3 5.
6. m∠1 + m∠3 = 90° 6. sunsitution
7. 7.
Answer:
Kindly rewrite the question clearly.
