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3 years ago

What is the volume of this figure? 1 unit 1 unit 1 unit

Mathematics

2 answers:

ra1l [238]3 years ago

3 0

Answer:

1 simply 1

Step-by-step explanation:

1*1*1=1

kifflom [539]3 years ago

3 0

1 quart 1 mm and Cubic inch

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A line segment has endpoints Q(-16, -12) and R(21, -8).

gulaghasi [49]

Answer:

(2.5, - 10 )

Step-by-step explanation:

given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( $\frac{x_{1}+x_{2} }{2}$ , $\frac{y_{1}+y_{2} }{2}$ )

here (x₁, y₁ ) = (- 16, - 12 ) and (x₂, y₂ ) = (21, - 8 ) , then

midpoint = ( $\frac{-16+21}{2}$ , $\frac{-12-8}{2}$ ) = ( $\frac{5}{2}$ , $\frac{-20}{2}$ ) = (2.5, - 10 )

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2 years ago

Tierra bought 4 3/8 yards blue ribbon and 2 1/8 yards yellow ribbon for a craft project. How much more blue ribbon than than yel

PolarNik [594]

She bought 2 1/4 more blue ribbon.

4 3/8 - 2 1/8 = 2.25
2.25= 9/4
9/4= 2 1/4

-Katie ;)

4 0

3 years ago

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Select all the expressions that equal.. *see picture for problem*

kupik [55]

Answer:

Step-by-step explanation:

oknjbgfkdfrgn jnfbfl

7 0

3 years ago

300 divided by 3 x 33

Airida [17]

300/3=100

100*33=3300

3 0

3 years ago

a pyramid whose altitude is 5ft weighs 800lbs. at what distance from its vertex must it be cut by a plane parallel to its base s

slavikrds [6]

A structure which has a square base and four triangular sides meeting at a point is called pyramid.

At distance of 3.97 feet from its vertex , pyramid is cut by plane so that the two solids of equal weight will be formed.

<u>It is assumed that weight of pyramid is proportional to its volume.</u>

So, $w = k V$ , where V is volume of original pyramid and v is volume of small pyramid and k is constant.

Let us consider that at h distance, pyramid is cut from its vertex. So a small pyramid is also formed.

Assume that base area of original pyramid is A and base of small pyramid is a.

Volume of original pyramid is, $V= \frac{1}{3} *A* 5$

So, weight of original pyramid, $W = k *(\frac{1}{3} *A* 5) = 800$

Volume of small pyramid is, $v = \frac{1}{3}* a* h$

So, weight of small pyramid, $w = k*(\frac{1}{3}* a* h)=400$

<u>Since, base and height of small pyramid and original pyramid are in proportion.</u>

So, $\frac{a}{A} = (\frac{h}{5}) ^{2}$

$a = (\frac{h}{5} )^{2}A$

Substituting value of a in equation $k*(\frac{1}{3}* a* h)=400$

So, $k*(\frac{1}{3}* \frac{h^{2} }{25}A * h)=400$

$(k*\frac{1}{3}* A*5)*\frac{1}{5} *\frac{h^{2} }{25} * h)=400$

Since, $(k *\frac{1}{3} *A* 5) = 800$ , substitute in above equation.

So, $800*\frac{h^{3} }{125}=400\\\\h^{3}=\frac{125}{2}\\\\h=\sqrt[\frac{1}{3} ]{62.5}\\\\h=3.97 feet$

Learn more:

brainly.com/question/17950304

6 0

2 years ago

Read 2 more answers