maybe try quizzlet that would really help i swear
Okay, ask yourself this : how many times does 6 goes into 30?
6 and 1 = 6
6 and 2 = 12
6 and 3 = 18
6 and 4 = 24
6 and 5 = 30
6 goes into 30 a number of 5 times. And so that means that :
60 and 1 make 60.
60 and 2 make 120
60 and 3 make 180.
60 and 4 make 240
60 and 5 make 300
FIVE (5) groups of 60 make 300.
<u>Solution for question 5:</u>
f(x) = 4x - 8
To find f^-1(x) write it as an equation:
y = 4x - 8
Then take x to left and y to right;
x = 4y - 8
Then solve for y;
y = (x + 8)/4 = x/4 + 2
Your y is the inverse of f(x) = 4x - 8
f^-1(x) = x/4 + 2
Answer:
120 degrees
Step-by-step explanation:
Since p is parallel to q, <6 and <8 are congruent because of corresponding angles.
m<8=m<6
120=m<6
Since m<8 is 120, and the two angles are congruent, the m<6 is also 120 degrees.
Answer:
3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3
(x-1/3)^2 is greater or equal to zero
3(x-1/3)^2 is greater or equal to zero
and 2/3 is greater than zero
So there sum is greater than zero
Proved
Step-by-step explanation:
3x^2 -2x + 1 =3(x^2-2/3x+1/3)
Consider x^2-2/3x+1/3
Remember that (a-b)^2 =a^2-2ab+b^2
x^2=a^2
a=x
-2/3x= -2*x*b
b=1/3
S0 (x-1/3)^2= x^2-2/3x+1/9
x^2-2/3x+1/3= x^2-2/3x+1/9+1/3-1/9= (x-1/3)^2+2/9
3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3
(x-1/3)^2 is greater or equal to zero
3(x-1/3)^2 is greater or equal to zero
and 2/3 is greater than zero
So there sum is greater than zero
Proved
