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Viktor [21]
3 years ago
9

How to do this answer

Mathematics
2 answers:
ELEN [110]3 years ago
6 0
15,16,17,18,18,19,20
dmitriy555 [2]3 years ago
4 0
5, 10, 15, or 1 , 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15,
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The m∠B is two more than three times the measure of ∠C. If ∠B and ∠C are complementary angles, find the measures of both angles.
allsm [11]

Answer:

B = 68°  and  C = 22°

Step-by-step explanation:

Let angle B's measure be B and angle C's measure be C.

Also note that complementary means that they sum to 90.

Now:

<u>The m∠B is two more than three times the measure of ∠C:</u>

we can write:

B = 3C + 2

<u>If ∠B and ∠C are complementary angles:</u>

B + C = 90

Putting 1st equation in 2nd, we get:

B + C = 90

3C + 2 + C = 90

4C = 90 - 2

4C = 88

C = 88/4 = 22

Now B = 3C + 2, so

B = 3(22) + 2 = 68

Hence, B = 68 degrees and C = 22 degrees

7 0
3 years ago
The radius of a clock face is 8.5 centimeters. what is circumfe0rence of clock?
kondor19780726 [428]

Answer:

The circumference of clock is, 53.38 cm

Step-by-step explanation:

Circumference(C) of the circle is given by:

C = 2 \pi r          ....[1]

where, r is the radius of the circle.

As per the statement:

the radius of a clock face is 8.5 centimeters

⇒r = 8.5 cm

Use\pi = 3.14

Substitute the given values in [1] we have;

C = 2 \cdot 3.14 \cdot 8.5

Simplify:

C = 53.38 cm

Therefore,  the circumference of clock is, 53.38 cm

7 0
3 years ago
Read 2 more answers
Please help! The sum of two angles formed by the intersection of two lines is 50°. Find the measures of the angles.
vichka [17]

Step-by-step explanation:

AB + BC = AC

50° + BC = 180°

BC = 180° - 50°

BC = 130°

AB = 50°

BC = 130°

AC = 180°

3 0
3 years ago
Find the area of the regular polygon. Give the answer to the nearest tenth.
k0ka [10]
I'm taking radius to be half of the side length.Then one side is 26 cm and the area of a square is the length of a side squared.A=26^2=676So,C) 676
7 0
4 years ago
Read 2 more answers
Listed below are the number of years it took for a random sample of college students to earn bachelor's degrees (based on data f
schepotkina [342]

Answer:

a) Mean = 6.5, sample standard deviation = 3.50

b) Standard error = 0.7826

c) Point estimate = 6.5

d) Confidence interval:  (5.1469 ,7.8531)

Step-by-step explanation:

We are given the following data set for students to earn bachelor's degrees.

4, 4, 4, 4, 4, 4, 4.5, 4.5, 4.5, 4.5, 4.5, 4.5, 6, 6, 8, 9, 9, 13, 13, 15

a) Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{130}{20} = 6.5

Sum of squares of differences = 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 4 + 4 + 4 + 4 + 4 + 4 + 0.25 + 0.25 + 2.25 + 6.25 + 6.25 + 42.25 + 42.25 + 72.25 = 233.5

S.D = \sqrt{\frac{233.5}{19}} = 3.50

b) Standard Error

= \displaystyle\frac{s}{\sqrt{n}} = \frac{3.50}{\sqrt{20}} = 0.7826

c) Point estimate for the mean time required for all college is given by the sample mean.

\bar{x} = 6.5

d) 90% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.10} = \pm 1.729  

6.5 \pm 1.729(\frac{3.50}{\sqrt{20}} ) = 6.5 \pm 1.3531 = (5.1469 ,7.8531)

e) No, the confidence interval does not contain the value of 4 years. Thus, confidence interval is not a good estimator as most of the value in the sample is of 4 years. Most of the sample does not lie in the given confidence interval.

5 0
4 years ago
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