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3 years ago

Altitudes are concurrent segments.

1 answer:

3 0

All four of these types of lines or line segments within triangles are concurrent, meaning that the three medians of a triangle share intersecting points, as do the three altitudes, mid-segments, angle bisectors, and perpendicular bisectors. The intersecting point is called the point of concurrency

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consider the function and then use calculus to answer the questions that follow 1 1/x 5/x^2 1/x^3 (a) Find the interval(s) where

boyakko [2]

Answer:

a) $X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)$

b) $Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0 )$

Step-by-step explanation:

From the question we are told that

The Function

$f(x)=1+\frac{1}{x} +\frac{5}{x^2} +\frac{1}{x^3}$

Generally the differentiation of function f(x) is mathematically solved as

$f(x)=1+\frac{1}{x} +\frac{5}{x^2} +\frac{1}{x^3}$

$f(x)=\frac{x^3+x^2+5x+1}{x^2}$

Therefore

$f'(x)=\frac{x^2+10x+3}{x^4}$

Generally critical point is given as

$f'(x)=0$

$\frac{x^2+10x+3}{x^4}=0$

$x=-5 \pm\sqrt{22}$

Generally the maximum and minimum x value for critical point is mathematically solved as

$f'(-5 \pm\sqrt{22})$

Where

Maximum value of x

$f'(-5 +\sqrt{22})$

Minimum value of x

$f'(-5 +\sqrt{22})$

Therefore interval of increase is mathematically given by

$f'(-5 -\sqrt{22}),f'(-5 +\sqrt{22})$

$f(x)$

Therefore interval of decrease is mathematically given by

$(-\infty,-5 -\sqrt{22}),f'(-5 +\sqrt{22},0),(0,\infty)$

Generally the second differentiation of function f(x) is mathematically solved as

$f''(x)=\frac{2(x^2+15x+6)}{x^5}$

Generally the point of inflection is mathematically solved as

$f''(x)=0$

$x^2+15x+6=0$

Therefore inflection points is given as

$x=\frac{1}{2} (-15 \pm \sqrt{201}$

$f''(x)>0,\frac{1}{2}(-15-\sqrt{201})$

a)Generally the concave upward interval X is mathematically given as

$X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)$

$f''(x)$

b)Generally the concave downward interval Y is mathematically given as

$Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0 )$

5 0

3 years ago

What is the slope of a line that is perpendicular to the line whose equation is 2x + y = 4

wel

The slope of the line of the equation given is -2 (by solving for y, you get y = -2x+4).

So, in order to be perpendicular, you must take the negative reciprocal.

The slope would be -1/2.

6 0

3 years ago

Read 2 more answers

Is it just me or do you guys get annoyed when people give us a whole explanation like, I only need the letter of the answer.

Oduvanchick [21]

Answer:

Yes lol

Step-by-step explanation:

Well the app says it helps people learn the answers but when I'm in a test i just look at letters:)

7 0

3 years ago

Read 2 more answers

a box of cereal weighs 550 g. There is enough cereal for 10 servings. How many grams of cereal are there per serving?

prisoha [69]

Answer:

55 grams per serving

Step-by-step explanation:

To find the number of grams per serving, we take to total grams and divide by the number of servings. The total grams is 550 and the number of servings is 10

grams per servings = 550/10 = 55 grams per serving

7 0

3 years ago

It takes an airplane 5/12 of a minute to fly 3/4 of a mile. What is the airplanes speed per minute?

Nikitich [7]

To make this a little easier, you would want to turn 3/4 into 9/12, to match 5/12's denominator.

You would then just add 7/1 to both fractions

(5/12+7/1=12/12 or 1 minutes)
(9/12+7/1=16/12=1 1/3)

So your answer would be 1.333... miles per minute

Hope this helps

7 0

3 years ago