Cot x= cosx/sinx =√3
tan x= 1/ √3
cos x = √2 /2
x= 45
tan45= 1
tan x= -4/3
csc x= 13/5
1/sin x = 13/5
sin x= 5/13
x=22.62
tan x= 5/12
Answer:
5.36
Step-by-step explanation:
Given that:
<BAD = <CAE, therefore, BD = EC
Let's take x to be the length of BD = EC
BD + DE + EC = BC
BC = 20,
BD = EC = x
DE ≈ 9.28
Thus,
x + 9.28 + x = 20
x + x + 9.28 = 20
2x + 9.28 = 20
Subtract 9.28 from both sides
2x + 9.28 - 9.28 = 20 - 9.28
2x = 10.72
Divided both sides by 2 to solve for x
![\frac{2x}{2} = \frac{10.72}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2x%7D%7B2%7D%20%3D%20%5Cfrac%7B10.72%7D%7B2%7D%20)
![x = \frac{10.72}{2}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cfrac%7B10.72%7D%7B2%7D%20)
![x = 5.36](https://tex.z-dn.net/?f=%20x%20%3D%205.36%20)
BD ≈ 5.36
6.6c - 3.6c - 2.3c = 0.7c
3.3m² + 4.9m² = 8.2²
=0.7c + 8.2²