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laila [671]
3 years ago
9

Given the function, y= x-4/x^2-4, choose the correct x-intercept(s).

Mathematics
1 answer:
Lerok [7]3 years ago
6 0

the correct x intercept would be 1 and -4 i believe!

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What are the coordinates of the point LaTeX: \frac{3}{4}\:3 4of the way from A to B? coordinate plane with line segment AB. Poin
egoroff_w [7]

Answer: \left(\dfrac{-7}{2},\dfrac{5}{4}\right).

Step-by-step explanation:

It is given that Point A is at (-5, -4) and point B at (-3, 3).

We need to find the coordinates of the point which is 3/4 of the way from A to B.

Let the required point be P.

AP:AB=3:4

AP:PB=AP:(AB-AP)=3:(4-1)=3:1

It means, point P divides segment AB in 3:1.

Section formula:  If a point divides a line segment in m:n, then

\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

Using section formula, we get

P=\left(\dfrac{3(-3)+1(-5)}{3+1},\dfrac{3(3)+1(-4)}{3+1}\right)

P=\left(\dfrac{-9-5}{4},\dfrac{9-4}{4}\right)

P=\left(\dfrac{-14}{4},\dfrac{5}{4}\right)

P=\left(\dfrac{-7}{2},\dfrac{5}{4}\right)

Therefore, the required point is \left(\dfrac{-7}{2},\dfrac{5}{4}\right).

6 0
3 years ago
The equation of a line is given below. 6x -4y = 24. Find the x-intercept and the Y-intercept then use them to graph the line
ipn [44]

Answer:

x intercept is 4 and the y intercept is -6

Step-by-step explanation:

x-int:

6x=24

x=4

y-int:

-4y=24

y=-6

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3 years ago
If x^2+y^2=1, what is the largest possible value of |x|+|y|?
Marianna [84]

If <em>x</em>² + <em>y</em>² = 1, then <em>y</em> = ±√(1 - <em>x</em>²).

Let <em>f(x)</em> = |<em>x</em>| + |±√(1 - <em>x</em>²)| = |<em>x</em>| + √(1 - <em>x</em>²).

If <em>x</em> < 0, we have |<em>x</em>| = -<em>x</em> ; otherwise, if <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>.

• Case 1: suppose <em>x</em> < 0. Then

<em>f(x)</em> = -<em>x</em> + √(1 - <em>x</em>²)

<em>f'(x)</em> = -1 - <em>x</em>/√(1 - <em>x</em>²) = 0   →   <em>x</em> = -1/√2   →   <em>y</em> = ±1/√2

• Case 2: suppose <em>x</em> ≥ 0. Then

<em>f(x)</em> = <em>x</em> + √(1 - <em>x</em>²)

<em>f'(x)</em> = 1 - <em>x</em>/√(1 - <em>x</em>²) = 0   →   <em>x</em> = 1/√2   →   <em>y</em> = ±1/√2

In either case, |<em>x</em>| = |<em>y</em>| = 1/√2, so the maximum value of their sum is 2/√2 = √2.

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Joe is positive 986 yards

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