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3 years ago

Help me plz this is hard

Mathematics

1 answer:

cricket20 [7]3 years ago

3 0

you first use distributive property for the multiplication

[(2*4x)-(2*11)]+9=19

8x-22+9=19

Then, you need to leave the variable alone moving all the other numbers with the opposite operation (addition to substraction, substraction to addition, multiplication to division, division to multiplication)

8x=19+22-9

8x=(19+22)-9

8x=41-9

8x=32

Then as 8 and x are multiplying you pass it dividing

x=32/8

x=4

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How much time should be allowed for a 392-km car trip if the car will be traveling at 120km/h

Diano4ka-milaya [45]

Answer:3hrs 16min

Step-by-step explanation:

392/120 = 49/15 hours = 3 hours + 4/15 hours = 3 hours + 4/15 x 60 min = 3 hours + 16 min

5 0

2 years ago

Can anyone solve this correctly?

andrew-mc [135]

Answer:

A. $200.96 \: {ft}^{2}$

Step-by-step explanation:

Corral is circular in shape.

Radius of the corral would be be the distance from the post to the edge of the corral.

-> r = 8 ft

$A(grass\: eaten) = \pi {r}^{2} \\ \\ = 3.14 {(8)}^{2} \\ \\ = 200.96 \: {ft}^{2}$

3 0

2 years ago

Can you fill in the blanks. Thx

maria [59]

Answer:

Answer is below

Step-by-step explanation:

Download docx

4 0

2 years ago

Select the relations that are functions.

Arlecino [84]

Answer:

Depending on how the input of each function defined,

The first choice $\left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace$ ,
The third choice $\left\lbrace(1, a),\, (2, a), \, (3, a)\right\rbrace$
The fourth choice $\left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace$

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

be defined for all elements in the domain, and
map each element from the domain to exactly one element in the range.

The second choice can't be a function since the element $a$ from the domain is mapped to more than one element in the range.

Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be $\lbrace a,\, 6, \, C\rbrace$ . Similarly, the domain for the third and fourth relations should be $\lbrace 1,\, 2, \, 3\rbrace$ and $\lbrace a,\, b, \, c\rbrace$

8 0

3 years ago

Need help plz..........

boyakko [2]

Subtraction property of equality
2/3y = -6
2/3y × 3/2 = -6 × 3/2
multiplication property of equality
y = -9

8 0

3 years ago