Answer:
A theorem stating that the square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of the lengths of the other sides. It is mathematically stated as c2 = a2 + b2, where c is the length of the hypotenuse and a and b the lengths of the other two sides.
Step-by-step explanation:
Answer: The correct answer is the second one
Step-by-step explanation:
Answer:
1 is 3
2 is-4
3 undefined
4 is 0
5 undefined
6 1.25
7 1.5
8 5
9 -2
10 -4
11 6
12 undefined
13 0
14 -1
15 2
16 -9
17 4
18 5
Step-by-step explanation:
Check the picture below, so the square looks more or less like so, since it has all equal sides, then we can simply get the distance of TE and multiply it times 4 and that's the perimeter.
![~~~~~~~~~~~~\textit{distance between 2 points} \\\\ T(\stackrel{x_1}{-1}~,~\stackrel{y_1}{3})\qquad E(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ TE=\sqrt{[-2 - (-1)]^2 + [-3 - 3]^2}\implies TE=\sqrt{(-2+1)^2+(-6)^2} \\\\\\ TE=\sqrt{(-1)^2+(-6)^2}\implies TE=\sqrt{37}~\hfill \stackrel{\textit{4 times that much}}{4\sqrt{37}}](https://tex.z-dn.net/?f=~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20T%28%5Cstackrel%7Bx_1%7D%7B-1%7D~%2C~%5Cstackrel%7By_1%7D%7B3%7D%29%5Cqquad%20E%28%5Cstackrel%7Bx_2%7D%7B-2%7D~%2C~%5Cstackrel%7By_2%7D%7B-3%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20TE%3D%5Csqrt%7B%5B-2%20-%20%28-1%29%5D%5E2%20%2B%20%5B-3%20-%203%5D%5E2%7D%5Cimplies%20TE%3D%5Csqrt%7B%28-2%2B1%29%5E2%2B%28-6%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20TE%3D%5Csqrt%7B%28-1%29%5E2%2B%28-6%29%5E2%7D%5Cimplies%20TE%3D%5Csqrt%7B37%7D~%5Chfill%20%5Cstackrel%7B%5Ctextit%7B4%20times%20that%20much%7D%7D%7B4%5Csqrt%7B37%7D%7D)
