Answer:
The equation is:
f (t) = 4 + 5 (1 - cos (2pi t / 2))
Step-by-step explanation:
with the previous exercise we look for the equation for h = f (t)
So the data we have are
Wheel diameter = 10m (wheel radius = 5m)
1 wheel gets 1 revolution in 2 minutes.
the beginning of a entry will be related to that f (0) = 4
our wish is that f (z) get at least 4 with an amplitude of 5 (this value determines the radius of the wheel) for 2 minutes
with this the particle f (t) is transformed into
f (t) = 4 + 5 (1 - cos (2pi t / 2))
We know that the maximum value of cos in t will be 0, 1 -cos has minutes, the result will be as follows:
f (t) = 4 + 5 (1 - cos (2pi t / 2))
Answer:
Hi! The answer to your question is C. 52
Step-by-step explanation:
☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆
☆Brainliest is greatly appreciated!☆
Hope this helps!
- Brooklynn Deka
For this case, the first thing we must do is define variables:
x: number of pillowcases
y: number of sheets
We now write the system of equations:
2x + 5y = 40
x = 2y
Solving the system we have:
x = 8.9
y = 4.4
Answer:
The maximum number of pillowcases she could have purchased is:
x = 8 (spent less than $ 40)
The maximum possible volume of this type of box that can be made from a 20 cm by 20 cm square of paper is 512cm³.
<h3>How to calculate the volume?</h3>
From the information, when the side of 1cm are cut, this will become an open box. The volume will be:
= 18 × 18 × 1
= 324cm³
Also, when 2cm is cut, the volume will be:
= 16 × 16 × 2
= 512cm³
Learn more about volume on:
brainly.com/question/1972490
#SPJ1
Answer:
Bag 1: 20
Bag 2: 40
Step-by-step explanation:
Let x be the amount taken out of bag 2
Then the amount left in each bag can be written as:
Bag 1: 50-3x
Bag 2: 50-x
Since we know that half of bag 2 is bag 1, that gives us:
50-3x = 1/2(50-x)
-> 50-3x = 25-x/2
Now lets isolate x and solve:
25 = 5x/2
-> 50 = 5x
-> x = 10
So plug x bag in for the original equations:
Bag 1: 50-3x = 50-3(10) = 20
Bag 2: 50-x = 50-10 = 40