Question:
If a sample of 2 hammer is selected
(a) find the probability that all in the sample are defective.
(b) find the probability that none in the sample are defective.
Answer:
a 
b 
Step-by-step explanation:
Given
--- hammers
--- selection
This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities
Solving (a): Probability that both selection are defective.
For two selections, the probability that all are defective is:
Solving (b): Probability that none are defective.
The probability that a selection is not defective is:
For two selections, the probability that all are not defective is:
Answer:
<em>D. Obtuse</em>
Step-by-step explanation:
"Given that he is male" is an important phrase here. The "given" in any probability problem is often important. This tells us "only focus on the males" because we know 100% that whoever we picked, the person is a male.
So we only focus on the "male" column. Use a highlighter to mark this column or cover up the other values if they are too distracting. There are 51 males total (bottom row) and 39 males had a flu shot (top row)
Divide the two values: 39/51 = (13*3)/(17*3) = 13/17
Answer: 13/17
Area of the trapezium = 1/2(18 + 6) x 12
Area of the trapezium = 144 in²
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Answer: Area = 144 in²
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WXY = XYW ( = 41 ) ⇒ XYW is a isosceles triangle
⇒ XW = YW
⇒ 54 = 6x + 6
⇒ 6( x + 1 ) = 54
⇒ x + 1 = 9
⇒ x = 8
ok done. Thank to me :>
