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sertanlavr [38]
3 years ago
14

What are the combination of stressed and unstressed syllables for these?​

Mathematics
1 answer:
Leviafan [203]3 years ago
5 0

Answer:

Step-by-step explanation:

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What positive whole number can you multiply by 3 and add1,or multiply by 2 and add 8?
Vilka [71]

Answer:

7 is the positive whole number which we can multiply by 3 and add 1, or multiply by 2 and add 8; and it will give the same answer.

Step-by-step explanation:

Multiplying the positive whole number 7 by 3 and adding 1 will get:

(7 × 3) + 1 = 21 + 1 = 22

Multiplying the positive whole number 7 by 2 and adding 8 will get:

(7 × 2) + 8 = 14 + 8 = 22

Therefore, 7 is the positive whole number which we can multiply by 3 and add 1, or multiply by 2 and add 8; and it will give the same answer.

3 0
3 years ago
What is the y-intercept, b, of the additive relationship represented by this table?
mina [271]

Answer:

  • b = 3

Step-by-step explanation:

Use the table to find the slope and y-intercept

<u>Find the slope:</u>

  • m = (6 - 4)/(3 - 1) = 2/2 = 1

<u>Find b using the pair (1, 4):</u>

  • 4 = 1*1 + b
  • b = 4 - 1
  • b = 3

<u>The line is:</u>

  • y = x + 3

The y-intercept is 3

8 0
3 years ago
Read 2 more answers
I need help ASAP!!<br> I just need help with problem one quick!
Misha Larkins [42]

Answer:

a. 5

b. -5

c. 13

d. -5

e. -13

f. 13

g. 5

h. -13

6 0
3 years ago
HELPPP PLSSSS ITS ALMOST DUE IN 1 HOUR WILL GIVE BRAINLIEST THANKS AND 5 STARSSS
svp [43]

Answer:Its been 5 hours. so 85 - 82 = X. X times 0.6 = 5 then translate to 5 hours.

Step-by-step explanation:

7 0
2 years ago
474 ( ) 548 42. - 8 how do I arrive at this answer.<br>​
dexar [7]

9514 1404 393

Answer:

  (64x^28)/(5y^22)

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)^c = a^(bc)

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

__

First, eliminate the outside exponent on the left factor. Then use the above rules to combine factors with the same base.

  \displaystyle\left(\frac{4x^4}{5y^6}\right)^5\cdot\left(\frac{5^4y^8}{4^2x^{-8}}\right)=\frac{(4^5x^{20})(5^4y^8)}{(5^5y^{30})(4^2x^{-8})}=4^{5-2}5^{4-5}x^{20-(-8)}y^{8-30}\\\\=4^35^{-1}x^{28}y^{-22}=\boxed{\frac{64x^{28}}{5y^{22}}}

5 0
3 years ago
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