4tan^(2)x-((4)/(cotx))+sinxcscx
Multiply -1 by the (4)/(cotx) inside the parentheses.
4tan^(2)x-(4)/(cotx)+sinxcscx
To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is cotx. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.
4tan^(2)x*(cotx)/(cotx)-(4)/(cotx)+sin...
Complete the multiplication to produce a denominator of cotx in each expression.
(4tan^(2)xcotx)/(cotx)-(4)/(cotx)+(cot...
Combine the numerators of all expressions that have common denominators.
<span>
(4tan^(2)xcotx-4+cotxsinxcscx)/(cotx)</span>
Answer:
x= -10
Step-by-step explanation:
Subtract 8x from 4x ( -4x )
-4x-34=6
Add 34 to 6 ( 40 )
-4x=40
Divide by -4 ( -10 )
x= -10
Answer:
Planet Distance from Sun (in Km) Distance in scientific notation
Mercury 57,909,000 Km 5.7909 X 10^3
Earth 150.33 Million Km 1.50.33 X 10^6
Mars 2.10.06 Million Km 2.1006 X 10^6
Jupiter 768.26 Million Km 7.6826 X 10^6
Neptune 4.4763 Billion Km 4.4763 X 10^9
Uranus 2.5957 Billion Km 2.5957 X 10^9
Saturn 1.4936 Billion Km 1.4936 X 10^9
Venus 107.95 Million Km 1.0795 X 10^6
Step-by-step explanation:
X² + x - 12 / x² - x - 20 ÷ 3x² - 24x + 45 / 12x² - 48x - 60
x² + x - 12 / x² - x - 20 * 12x² - 48x - 60 / 3x² - 24x + 45
<u>(x² + x - 12)(12x² - 48x - 60)</u>
(x² - x - 20)(3x² - 24x + 45)
<span><u>12x^4 - 48x³ - 60x² + 12x³ - 48x² - 60x - 144x² + 576x + 720</u>
</span>3x^4 - 24x³ + 45x² - 3x³ + 24x² - 45x - 60x² + 480x - 900
<span>
<u>12x^4 - 48x³ + 12x³ - 60x² - 48x² - 144x² - 60x + 576x + 720</u></span>
3x^4 - 24x³ - 3x³ + 45x² + 24x² - 60x² - 45x + 480x - 900
<u>12x^4 - 36x³ - 252x² + 516x + 720</u>
3x^4 - 27x³ + 9x² + 435x - 900
<u>12(x^4 - 3x³ - 21x² + 43x + 60) </u>
3(x^4 - 9x³ + 3x² + 145x + 300)
<u>4(</u><span><u>x^4 - 3x³ - 21x² + 43x + 60) </u>
</span><span> (x^4 - 9x³ + 3x² + 145x + 300)</span>
Answer: (d)
Step-by-step explanation:
Given
It takes 14 hours with 40 mph to reach the theatre
so, the distance traveled is given by
It is given that d is the distance from theatre to friend's house
So, d must be less than i.e.
So, the most appropriate option out of the given is option (d) as d must be less than 560 and it is possible that it maybe less than 160.