The height at time t is
h(t) = 144 - 16t²
When t = 0, then h = 144.
Therefore the height from the ground is 144 when the object is dropped.
When the object reaches the ground, h = 0.
Therefore
144 - 16t² = 0
t² = 144/16 = 9
t = 3 s
Answer:
The object reaches the ground in 3 seconds.
Answer:
r = t(r-3)
Step-by-step explanation:
t = r/r-3
r/r-3 = t
r = t x (r-3)
Answer:
417
Step-by-step explanation:
3(2+1-3)-212*2+1-4=?
3-212*2+1-4=?
3-423+1-4=?
420+1-4=?
421-4=?
417
