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cupoosta [38]
3 years ago
12

What is the integral of 1/(y²-1)

Mathematics
1 answer:
ANTONII [103]3 years ago
3 0
Hello here is a solution : 

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Miguel is posting photos on a school website. He has 48 photos, and he is allowed to
weeeeeb [17]

Answer:

12p=48

Step-by-step explanation:

8 0
2 years ago
a student spends $48 on school supplies at a store where the sales tax is 7% what is the total cost of the supplies
Klio2033 [76]
51.36 is the answer.
The equation is total=original(1+% in decimal form)
4 0
3 years ago
Read 2 more answers
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
inn [45]

Answer:

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Step-by-step explanation:

The given expression is

\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}

First, we need to factor each denominator

\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}

So, the least common factor (LCF) is x(x-3)(x+3), because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Therefore, the expression is equivalent to

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

8 0
3 years ago
Read 2 more answers
What is the exact volume of the sphere?. . A.. 463.01 m3. . B.. 147.456 m3. . C.. 96.46 m3. . D.. 36.868 m3
Yakvenalex [24]
The volume of the sphere : ( r = 4.8 m )
V = 4/3 r³ π = 4/3 · ( 4.8 m )³ · 3.14 = 4/3 · 110.592 · 3.14 = 463.01 m³
Answer: A ) 463.01 m³
7 0
3 years ago
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An amusement park charges an admission fee of 30 dollars per person. The cost, C (in dollars), of admission for a group of p peo
Nuetrik [128]
All you have to do here is multiply 30 by the number of people
so..

cost = 30 \times 2
cost = 60

7 0
3 years ago
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