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cupoosta [38]
3 years ago
12

What is the integral of 1/(y²-1)

Mathematics
1 answer:
ANTONII [103]3 years ago
3 0
Hello here is a solution : 

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The value of a car depreciates by 15% each year. The value of the car when new is $14000. WHat will be the value of the car afte
deff fn [24]

Answer:

$11,900

Step-by-step explanation:

6 0
3 years ago
Evaluate this exponential expression.
Afina-wow [57]
It's -32 since 10-42=-32
8 0
3 years ago
Find the following when a = -3, b = 6, c = −4/5 9b−72a+1
Vadim26 [7]
271.

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8 0
2 years ago
Consider the differential equation x2y′′ − 9xy′ + 24y = 0; x4, x6, (0, [infinity]). Verify that the given functions form a funda
pantera1 [17]

Answer:

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

y= c_1x^4+c_2x^6

Step-by-step explanation:

Given equation is

x^2y'' - 9xy+24y=0

This Euler Cauchy type differential equation.

So, we can let

y=x^m

Differentiate with respect to x

y'= mx^{m-1}

Again differentiate with respect to x

y''= m(m-1)x^{m-2}

Putting the value of y, y' and y'' in the differential equation

x^2m(m-1) x^{m-2} - 9 x m x^{m-1}+24x^m=0

\Rightarrow m(m-1)x^m-9mx^m+24x^m=0

\Rightarrow m^2-m-9m+24=0

⇒m²-10m +24=0

⇒m²-6m -4m+24=0

⇒m(m-6)-4(m-6)=0

⇒(m-6)(m-4)=0

⇒m = 6,4

Therefore the auxiliary equation has two distinct and unequal root.

The general solution of this equation is

y_1(x)=x^4

and

y_2(x)=x^6

First we compute the Wronskian

W(x)= \left|\begin{array}{cc}y_1(x)&y_2(x)\\y'_1(x)&y'_2(x)\end{array}\right|

         = \left|\begin{array}{cc}x^4&x^6\\4x^3&6x^5\end{array}\right|

         =x⁴×6x⁵- x⁶×4x³    

        =6x⁹-4x⁹

        =2x⁹

       ≠0

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

y= c_1x^4+c_2x^6

5 0
3 years ago
Frank purchased an air conditioner for $3000. Its value depreciates at a rate of 8% each year. How much will the air conditioner
Lina20 [59]

Answer:

$2280

Step-by-step explanation:

Given: Cost of Air conditioner= $3000.

            Rate of depreciation= 8%

            Number of year= 3 years.

Now, finding the depreciation for 3 years.

Depreciation= \frac{Cost\ of\ air\ conditioner\times rate\ of\ depreciation\times years}{100}

Amount of depreciation= \frac{\$ 3000\times 8\times 3}{100} = \$ 30\times 24

∴ Amount of depreciation in 3 years is $720.

Cost of Air conditioner after 3 years= Original\ cost - Amount\ of\ depreciation

⇒ Cost of Air conditioner after 3 years= \$ 3000-\$ 720= \$ 2280.

∴ Cost of Air conditioner in 3 years is $2280.

5 0
3 years ago
Read 2 more answers
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