Answer:
1. Is
2. Is
3. Is not
4. Is not
lol give me brainliest please!
This question not incomplete
Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
m
Step-by-step explanation:
Square area: m²
The formula for finding the square area: m×m=m²
m²=√(m²)=m
one side of the square is equal to m
Answer:
The required number is 7.
Dividing by this gives the perfect square 676.
Step-by-step explanation:
Finding the prime factors:
2) 4732
2) 2366
7) 1183
13)169
13
So 4372
= 2^2 * 7 * 13^2
= 4 *169 * 7
= 676 * 7
Now 676 is a perfect square so the answer is 7.
= 1283 * 4.
Answer is 1283.
Answer:
B. 3 to 2
Step-by-step explanation:
I calculated it logically
