A triangle should have 3 points and 3 sides. Let say that the point is ABC. Then the sides would be AB, AC and BC.
There are 3 strings with a different length that can be put into the sides. Assuming the string can be used once, then the possible way would be:
3!/(1+3-3)!= 3!/1!= 3*2*1= 6 ways
Answer:
-34b4
Step-by-step explanation:
Since the variables are the same b4, you just add the constants (-16 & -18).
Answer:
a = 3, b = 2
Step-by-step explanation:
It is given that both the polynomials are equal.
Therefore, h(x) = k(x)
The formula for a come is V=πr^2h/3.
Answer:
D
Step-by-step explanation:
