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3 years ago

A 5/1 b 1/5 c 5/4 d 4/5

Mathematics

2 answers:

patriot [66]3 years ago

7 0

Answer:

The answer is b 1/5

Step-by-step explanation:

There are 5 sections in the spinner and 1 of the 5 is a three so it would be 1/5.

Delicious77 [7]3 years ago

6 0

The answer is b bc it can’t be 4/5 or 5/1 then it just to left

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| -4 + 5\2 | - (-x) =-3

Leto [7]

Answer:

x = -4.5

Step-by-step explanation:

<u><em>Solving the equation</em></u> :

$\left\vert -4+\frac{5}{2} \right\vert -\left( -x\right) =-3$

$\Longleftrightarrow \left\vert \frac{-8}{2} +\frac{5}{2} \right\vert +x =-3$

$\Longleftrightarrow \left\vert \frac{-8+5}{2} \right\vert +x =-3$

$\Longleftrightarrow \left\vert \frac{-3}{2} \right\vert +x =-3$

$\Longleftrightarrow \frac{3}{2} +x =-3$

$\Longleftrightarrow x =-3-\frac{3}{2}$

$\Longleftrightarrow x =-\frac{6}{2} -\frac{3}{2}$

$\Longleftrightarrow x = -(\frac{6}{2} +\frac{3}{2} )$

$\Longleftrightarrow x =-\frac{9}{2}$

$\Longleftrightarrow x =-4.5$

7 0

2 years ago

the specification for a plastic handle calls for a length of 6.0 inches +- .2 inches. The standard deviation of the process is e

erastova [34]

Answer:

USL = 6.2 inches

LSL = 5.8 inches

b) Cp = 1.33

Cpk = 0.67

Yes it meets all specifications

Step-by-step explanation:

The specification for a plastic handle calls for a length of 6.0 inches ± .2 inches. The standard deviation of the process is estimated to be 0.05 inches. What are the upper and lower specification limits for this product? The process is known to operate at a mean thickness of 6.1 inches. What is the Cp and Cpk for this process? Is this process capable of producing the desired part?

Given that:

Mean (μ) = 6.1 inches, Standard deviation (σ) = 0.05 inches and the length of the plastic handle is 6.0 inches ± .2

a) Since the length of the plastic handle is 6.0 inches ± .2 = (6 - 0.2, 6 + 0.2)

The Upper specification limits (USL) = 6 inches + 0.2 inches = 6.2 inches

The lower specification limits (LSL) = 6 inches - 0.2 inches = 5.8 inches

b) The Cp is given by the formula:

$Cp=\frac{(USL-LSL)}{6\sigma} =\frac{(6.2-5.8)}{6*0.05} =1.33$

The Cpk is given by the formula:

The upper specification limit lies about 3 standard deviations from the centerline, and the lower specification limit is further away, so practically all units will meet specifications

$Cpk=min(\frac{USL-\mu}{3\sigma},\frac{\mu -LSL}{3\sigma})=min(\frac{6.2-6.1}{3*0.05},\frac{6.1-5.8}{3*0.05})=min(0.67,2)=0.67$