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MAXImum [283]
2 years ago
14

Find the slope of the line passes through the points (1, -4) and (4,2)

Mathematics
1 answer:
nasty-shy [4]2 years ago
7 0
For
(x1,y1) and (x2,y2)
slope=(y2-y1)/(x2-x1)

(1,-4)
(4,2)
x1=1
y1=-4
x2=4
y2=2

slope=(2-(-4))/(4-1)=(2+4)/3=6/3=2

slope=2
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3 0
2 years ago
The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y – 4 = y minus 4 equals StartFra
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Answer:

Third option: y= \frac{1}{4}x+2

Step-by-step explanation:

<h3><em> The correct form of the exercise is: "The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y -4 = \frac{1}{4}(x -8). What is the slope-intercept form of the equation for this line?"</em></h3><h3><em /></h3>

<em> </em>The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

Given the equation of the line in Point-Slope form:

y -4 = \frac{1}{4}(x -8)

You need to solve for "y" in order to write the given equation of the line in Slope Intercept form.

Then, this is:

y -4 = \frac{1}{4}(x -8)\\\\y-4= \frac{1}{4}x-\frac{8}{4}\\\\y-4= \frac{1}{4}x-2\\\\y= \frac{1}{4}x-2+4\\\\y= \frac{1}{4}x+2

You can identify that the slope "m" is:

m=\frac{1}{4}

And the y-interecept "b" is:

b=2

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3 years ago
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