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bixtya [17]
3 years ago
11

A local school needs to paint the floor of its theater room, where the length of the floor, x, is at least 12 feet. The width of

the floor is 4 feet less than the length. It will have a stage and a closet, and the remaining area of the floor will be painted. The dimensions are shown in the diagram:
rectangle with length of x ft and width of x minus 4 ft, right triangle inside labeled stage with height of x minus 4 ft and base of 8 ft, rectangle inside labeled closet with length of 8 ft and width of 4 ft, the rest of the rectangle is labeled floor

Let A represent the painted area, in square feet, of the floor. Choose the correct equation to solve for area (A).

A.)A = x(x − 4) − 0.5(8)(x − 4) − 4(8)
B.)A = x(x − 4) − (8)(x − 4) − 4(8)
C.)A = x(x − 4) + (8)(x − 4) + 4(8)
D.)A = x(x − 4) + 0.5(8)(x − 4) + 4(8)
Mathematics
2 answers:
yuradex [85]3 years ago
8 0

Answer: The correct equation is the option A.)A = x(x − 4) − 0.5(8)(x − 4) − 4(8)

Step-by-step explanation:

To find the painted area of the theater room in square feet, the following steps must be followed:

1. Determine the area of the theater room

Length: x

Width: x-4

A (theater room) = x (x-4)

2. Determine the area of the right triangle

Height: x-4

Base: 8

A (right triangle) = 0.5 (8) (x-4)

3. Determine the area of the rectangle inside labeled closet

Length: 8

Width: 4

A (closet) = 8 (4)

4. The area to be painted will be the substraction between the total area of the theater room, less the area of the right triangle and less the area of the rectangle of the closet like this:

A= A(theater room) - A(right triangle) - A (closet)

A = x (x-4) -0.5 (8) (x - 4) - 4 (8)

Therefore, the correct equation to solve by area is option A

Travka [436]3 years ago
7 0

Answer: A

Step-by-step explanation: I took le test

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lubasha [3.4K]

Answer:

Solutions are (1,2) and (-1/2,5)

Don't forget to like rate and mark brainliest!

Step-by-step explanation:

y=6x^2-5x+1

y=-2x+4

<em>Substitute</em>

-2x+4=6x^2-5x+1

<em>Simplify</em>

0=6x^2-3x-3

<em>Solve by factoring</em>

(x-6/6)(x+3/6)=0

x-1=0, x+1/2=0

x=1, x=-1/2

<em>Plug x's into oringinal equation</em>

y=-2(1)+4, y=-2(-1/2)+4

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<em>Write out solutions</em>

(1,2) and (-1/2,5)

7 0
3 years ago
Jack's school is 6 km from his home. He goes to school by bus. One day on the way to school due to road construction the bus had
Setler79 [48]

Answer:

<h2>The bus was 1250 meters away from school</h2>

Step-by-step explanation:

Given that the total distance of the school from home is 6km

converting 6km to meters we have 6,000m

Since the bus stopped at 4750 meters from his home.

The remaining distance is the distance the bus is from his school

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3 years ago
Which measures are accurate regarding triangle JKL? Check all that apply.
mixas84 [53]

Answer:

Option (1), (3) and (6) is correct.

m∠K = 84° , k ≈ 3.7 units and KL ≈ 3.2 units.

Step-by-step explanation:

  Given : ∠J = 58° , ∠L = 38°  and length of side JK = 2.3 units.

We need to check all the options and choose that follows.

First we find the measure of ∠K

Using angle sum property , Sum of angles of a triangle  is 180°

⇒ ∠J + ∠k + ∠L = 180°

⇒ 58° + ∠k + 38° = 180°

⇒  ∠k + 96° = 180°

⇒  ∠k   = 180° - 96°

⇒  ∠k   = 84°

Also using sine rule on ΔJKL , we get,

\frac{KL}{\sin J}=\frac{JL}{\sin K}=\frac{JK}{\sin L}

Substitute the values, we get,

\frac{KL}{\sin 58^{\circ}}=\frac{k}{\sin 84^{\circ}}=\frac{2.3}{\sin 38^{\circ}}

Consider the last two ratios, we have,

\frac{k}{\sin 84^{\circ}}=\frac{2.3}{\sin 38^{\circ}}

{k}=\frac{2.3}{\sin 38^{\circ}}\times {\sin 84^{\circ}}

On solving we get,

{k}=3.71

Also, now consider the first and last ratio, we get,

\frac{KL}{\sin 58^{\circ}}=\frac{2.3}{\sin 38^{\circ}}

{KL}=\frac{2.3}{\sin 38^{\circ}}\times {\sin 58^{\circ}

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Thus, k ≈ 3.7 units and KL ≈ 3.2 units.

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5 0
4 years ago
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CaHeK987 [17]

Answer:

The number of ways in which students were chosen is 45 ways .

Step-by-step explanation:

Given as :

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The number of students chosen by teacher to go to library = y = 2

Let The number of ways in which students were chosen = n ways

<u>Now, According to question</u>

So,  number of ways in which students were chosen = _{y}^{x}\textrm{C}

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Or, n  = \frac{\L 10}{\L( 10-2)\times \L 2}

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So, The number of ways in which students were chosen = n = 45 ways

Hence,The number of ways in which students were chosen is 45 ways . Answer

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4 years ago
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Anni [7]

Answer:

23 %

Step-by-step explanation:

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6 0
3 years ago
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